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Elena L [17]
3 years ago
10

What is the first step when rewriting y = 6x2 + 18x + 14 in the form y = a(x – h)2 + k? 16 must be factored from 18x + 14 x must

be factored from 6x2 + 18x 6 must be factored from 6x2 + 14 6 must be factored from 6x2 + 18x
Mathematics
2 answers:
guajiro [1.7K]3 years ago
4 0
The first step is factoring out the 6 from the 6x2 + 18x. 
Tpy6a [65]3 years ago
3 0

Answer:

<em>" 6 must be factored from 6x^2 + 18x "</em>

Step-by-step explanation:

We are given a equation as:

y=6x^2+18x+14

On expressing the given equation in terms of y=a(x-h)^2+k

where h, k are real numbers; we get our quadratic equation as:

6(x-\dfrac{3}{2})^2+\dfrac{1}{2}

Here on comparing our equation with  y=a(x-h)^2+k we have :

h=\dfrac{3}{2} and  k=\frac{1}{2}.

This means that we have to first factor out '6' from the term 6x^2+18x

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Misha deposited $3,725 into a savings account 22 years ago. The account has an interest rate of 2.2% and the balance is currentl
Annette [7]
The compounding equation is A=P(1+ \frac{r}{n}) ^{nt}. So
 
6012.37 = 3725(1+ \frac{0.022}{n}) ^{22n}    Divide by 3725

1.6141= (1+ \frac{0.022}{n}) ^{22n}

Daily      = (1+ \frac{0.022}{365}) ^{22*365}
              = (1.000060274) ^{8030}
              = 1.6225
Monthly  = (1+ \frac{0.022}{12}) ^{22*12}
              = (1.0018333) ^{264}
              = 1.6218
Quarter  = (1+ \frac{0.022}{4}) ^{22*4}
              = (1.0055) ^{88}
              = 1.6204
Yearly  = (1+ \frac{0.022}{1}) ^{22*1}
              = (1.022) ^{22}
              = 1.6141

The answer is yearly.





5 0
3 years ago
Questions are shown in the picture, any help is appreciated! :)
cestrela7 [59]
A) 13 students
b) 13 students
c) 37 students
7 0
3 years ago
NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.
PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

y = 3x

We want everything below this line (line included), so the first inequality is

y \leq 3x

The line between the origin and B is

y = \dfrac{1}{3}x

We want everything above this line (line included), so the second inequality is

y \geq \dfrac{1}{3}x

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}

Which means

A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

B:\ 1

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0
3 years ago
Please help last question:((
jasenka [17]

Answer:

7. C(N(h))=33hx+460h

8. about $13.94 is the cost

Step-by-step explanation:

7. C(x)=(33x+460)(N(h))=(N(40)h)--C(x)=(33x+460)(40h)--C(x)=1320hx+18400h--simplified to C(N(h))=33hx+460h

8. C(N(10))=33(10)x+460(10)--C(N(10))=330x+4600--4600/330=about13.94

5 0
3 years ago
Which is equivalent to 8x−y+3x?
Tom [10]
Answer: 11x - y = 8x - y + 3x
4 0
3 years ago
Read 2 more answers
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