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4 years ago

Determine the volume of an 85-gram sample of gold at ST M

Chemistry

1 answer:

goldenfox [79]4 years ago

5 0

Answer:

Volume of gold is 9.64 L .

Explanation:

Given data:

Mass of gold = 85 g

Temperature = standard = 273 K

Pressure = standard = 1 atm

Volume of gold = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will calculate the number of moles of gold.

Number of moles = mass/molar mass

Number of moles = 85 g/ 197 g/mol

Number of moles = 0.43

1 atm × V = 0.43 mol ×0.0821 atm.L/ mol.K × 273 K

V = 9.64 atm.L / 1 atm

V = 9.64 L

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3 years ago

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Answer:- Third choice is correct, 17.6 moles

Solution:- The given balanced equation is:

Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4

We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.

From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.

It is a simple mole to mole conversion problem. We solve it using dimensional set up as:

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3 years ago

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