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3 years ago

What are the spectators ions in this reaction?

Chemistry

1 answer:

miv72 [106K]3 years ago

4 0

Answer:

Option C. Na⁺(aq) and Cl¯(aq)

Explanation:

From the question given above, we obtained the following:

Na₂SO₄(aq) + CaCl₂(aq) —> CaSO₄(s) + 2NaCl(aq)

Ionic Equation:

2Na⁺(aq) + SO₄²¯(aq) + Ca²⁺(aq) + 2Cl¯(aq) —> CaSO₄(s) + 2Na⁺(aq) + 2Cl¯(aq)

From the ionic equation above, we can see that Na⁺(aq) and Cl¯(aq) are present on both side of the equation.

Therefore, Na⁺(aq) and Cl¯(aq) are the spectator ions because they did not participate directly in the reaction.

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A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0

miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

$Q_{metal} - Q_{water} = 0$

$Q_{metal} = Q_{water}$

Where:

$Q_{water}$ - Heat received by water, measured in joules.

$Q_{metal}$ - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

$m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})$

The specific heat of the metal is cleared within equation above:

$c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}$

If we know that $m_{water} = 0.237\,kg$ , $m_{metal} = 0.244\,kg$ , $c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ , $T_{w,o} = 10\,^{\circ}C$ , $T_{m,o} = 100.10\,^{\circ}C$ and $T = 15.30\,^{\circ}C$ , the specific heat of molybdenum is:

$c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}$

$c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}$

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

5 0

3 years ago

Suppose a piece of silver jewelry contains 5.23×1022 atoms of silver (ag). part a how many dozens of silver atoms are in the pie

IgorC [24]

Answer:
number of dozens = 4.35834 * 10^21 dozens

Explanation:
A dozen contains 12 atoms. To know the number of dozens containing
5.23 * 10^22 atoms, all we have to do is cross multiplication as follows:
1 dozen ...........> 12 atoms
?? dozens ......> <span>5.23 * 10^22
number of dozens = (</span><span>5.23 * 10^22 *1) / (12)
number of dozens = 4.35834 * 10^21 dozens

Hope this helps :)</span>

7 0

3 years ago

Why do elements that make positive ions occur on the left side of the periodic table while those that make negative ions occur o

Lynna [10]

Answer:

Elements in the same group have the same number of valence electrons.

Explanation: Science.

8 0

3 years ago

The Law of _____states that substances combine in predictable proportions and that excess reactants remain unchanged.

RideAnS [48]

Answer: definite proportions.

Explanation:

1) The definite proportions law states that compounds will always have the same kind of atoms (elements) in the same mass proportion (ratios).

2) For example, a molecule of water will alwys have the same mass ratio of hydrogen atoms to oxygen atoms. That is what permits to obtain the chemical formula of the water molecule as H₂O.

The mass of the two hydrogen atoms will be in a fixed ratio respect to the mass of the oxygen atoms.

Then, if you have one reactant in less proportion than the other, respect to the ratio stated by the chemical formula of water, the former will react completely (it is the limiting reactant) with the corresponding (proportional) mass of the later. Then there will be an excess of the later reactant which will not react (will remain unchanged).

The reactants can only react in the proportion defined by the chemical formulas of the final products.

4 0

3 years ago

Read 2 more answers

The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determine how the cars perf

Leya [2.2K]

Answer:

It’s B just did it

Explanation:

6 0

3 years ago