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qwelly [4]
3 years ago
5

What are the spectators ions in this reaction?

Chemistry
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

Option C. Na⁺(aq) and Cl¯(aq)

Explanation:

From the question given above, we obtained the following:

Na₂SO₄(aq) + CaCl₂(aq) —> CaSO₄(s) + 2NaCl(aq)

Ionic Equation:

2Na⁺(aq) + SO₄²¯(aq) + Ca²⁺(aq) + 2Cl¯(aq) —> CaSO₄(s) + 2Na⁺(aq) + 2Cl¯(aq)

From the ionic equation above, we can see that Na⁺(aq) and Cl¯(aq) are present on both side of the equation.

Therefore, Na⁺(aq) and Cl¯(aq) are the spectator ions because they did not participate directly in the reaction.

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3 years ago
calculate the number of moles of sulfuric acid that is contained in 250 mL of 8.500 M sulfuric acid solution
san4es73 [151]

Answer : The moles of H_2SO_4 are, 2.125 mole.

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\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}

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