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deff fn [24]
3 years ago
14

A single gram of 235U fuel can heat and boil 2.49 x 107 g of water. What volume of water is this?

Chemistry
1 answer:
iogann1982 [59]3 years ago
6 0
You just have to convert the mass of water into volume.

To do that you use the density of water, which is about 1.0 g/ ml

So, from the formula of density D = M / V, you get V = M / D

=> V = 2.49 * 10^7 grams / 1.0 g / ml = 2.49 * 10 ^ 7 ml

You can pass that to liters using the conversion factor 1000 ml = 1 l

2.49 * 10^7 ml * 1 l / 1000 ml = 2.49 * 10^4 l = 24,900 l

Answer: 24,900 l
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