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2 answers:
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<>"Atomic particles. Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus. The electron cloud has a radius 10,000 times greater than the nucleus."<>
Explanation:
For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.
Putting the given values into the above equation as follows.
=
= 1902.81 J
Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.
= energy required =
= latent heat of vaporization
Therefor, calculate the value of energy required as follows.
=
=
= 12121.2 J
Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.
Value of = 1.06 J/g,
= (373 -339) K = 34 K
Hence, putting the given values into the above formula as follows.
=
= 983.892 J
Therefore, net heat required will be calculated as follows.
Q =
= 1902.81 J + 12121.2 J + 983.892 J
= 15007.902 J
Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.
Answer:
The concentration of acetic acid in the vinegar is 7,324 (%V/V)
Explanation:
The titration equation of acetic acid with NaOH is:
NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O
The moles required were:
1,024M×0,02500L = <em>0,02560 moles NaOH. </em>These moles are equivalent (By the titration equation) to moles of CH₃COOH. As molar mass of CH₃COOH is 60,052g/mol, the mass in these moles of CH₃COOH is:
0,02560 moles CH₃COOH×= <em>1,537g of CH₃COOH</em>
As density is 1,01g/mL:
1,537g CH₃COOH×= <em>1,522mL of CH₃COOH</em>
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As volume of vinegar in the sample is 20,78mL, the concentration of acetic acid in the vinegar is:
×100= <em>7,324 (%V/V)</em>
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I hope it helps!