Ask question

Ask question

All categories

4 years ago

10

Describe in general terms the structure of ionic solids such as nacl

1 answer:

allochka39001 [22]4 years ago

8 0

<span>Ionic compounds are chemical compounds in which ions are held together in a lattice structure by ionic bonds. They have a high melting and boiling point, and they have a high hardness and are very brittle. The cations and anions are stuck together in a sense. So in this case, sodium (Na) is attracted to Chlorine (Cl).</span>

You might be interested in

A balloon is filled with 1 mole of helium gas at 100 kPa of pressure and a

mylen [45]

Answer:

B) 0.025 $m^{3}$

Explanation:

Solution of the problem is in picture attached,

3 0

3 years ago

Whats is not a characteristic of the eye of a hurricane

Marina86 [1]

B. has the storms strongest winds is not a characteristic of the eye of a hurricane because in the eye it is actually completely calm.

Hope that helps u!!

5 0

3 years ago

Read 2 more answers

Which concept does the diagram show?

salantis [7]

Answer:

temperature

Explanation:

sorry if wrong

4 0

3 years ago

A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?

Licemer1 [7]

Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

$\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles$

Now we have to calculate the moles of $Br_2$

${\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles$

${\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles$

The balanced chemical reaction is,

$2Na(s)+Br_2(g)\rightarrow 2NaBr$

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium bromide

Now we have to calculate the percent yield of reaction

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%$

Therefore, the percent yield is, 93.4%

3 0

3 years ago

Explain why the electron configuration of 2-3-1 represents an atom in an excited state.

Allushta [10]

Answer:

The excited state electron configuration of an atom indicates the promotion of a valence electron to a higher energy state.

4 0

3 years ago