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Tamiku [17]
3 years ago
5

What is the correct description of the components of an ATP molecule?

Chemistry
1 answer:
frosja888 [35]3 years ago
4 0
It's adenosine triphosphate !

it has Penrose sugar and phosphate as backbone !
and nitrogenous base ... adenine.... in the middle !
You might be interested in
If a ball rolling down a hill is half way between the top and bottom, how much potential energy does the ball have compared to k
madreJ [45]

Answer:

The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)

Explanation:

The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.

If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.

If the gravitational field strength g is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.

If m denote the mass of this ball, the gravitational potential energy (\rm GPE) of this ball at height h would be {\rm GPE} = (m \cdot g) \cdot h, which is proportional to h\!.

The value of g near the surface of the earth is indeed approximately constant (typically g \approx 9.8\; \rm m \cdot s^{-2}.)

At halfway between the top and bottom of this hill, the height of this ball would be (1/2) of its initial value (the value when the ball was at the top of the hill.) Because the \rm GPE of this ball is proportional to its height, at halfway down the hill, the \rm GPE\! of this ball would also be (1/2)\! its initial value.

However, if there was no friction on this ball (and that the ball did not deshape,) that (1/2) of the initial \rm GPE\! of this ball was not lost. Rather, these (1/2)\! of the initial \rm GPE would have been converted to the kinetic energy (\rm KE) of this ball.

Hence, when the ball is halfway down the hill:

\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}.

\begin{aligned}& \text{KE halfway down the hill}\\  &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}.

Therefore:

\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}.

In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.

3 0
3 years ago
Can someone help me with this i don't understand it.
stealth61 [152]

Answer:

The subscript next to the letter "C" will always tell you the number of carbon atoms.

6 0
3 years ago
If 3 g of element C combine with 8 g of element D to
Scrat [10]
16 grams because you multiply 8x2
5 0
3 years ago
Calculate the pH of the following:
Brums [2.3K]

The pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution.

<h3>What is the pH?</h3>

What we call the pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution. We are aware that we can use the relation [H+]  [OH-]  = 1 * 10^-14 to handle the enormity of this problem.

Now, let us go about solving the problems;

1. pH = -log(1 x 10-7) = 7

2.  [H+]=  1 * 10^-14/ 1 x 10^-3

pH =  -log(  1 * 10^-11)

pH = 11

3. pH = -log( 1 x 10^-2)

pH = 2

4. pH = -log(  1 x 10^-10)

pH = 10

5.  [H+]=  1 * 10^-14/ 1 x 10^-8

[H+]=  1 * 10^-6

pH = 6

Learn more about pH:brainly.com/question/1528974

#SPJ1

6 0
2 years ago
The trend in electronegativity is F &gt;Cl &gt;Br; therefore, the most ionic compound (CH2F2) has the lowest boiling point, and
bulgar [2K]

Answer:

False

Explanation:

Increase in polarity of a molecule leads to higher boiling points. The more polar a molecule is, the higher the energy required to breaks intermolecular forces of attraction hence the higher the boiling point. This is the reason why ionic compounds and compounds having polar covalent bonds in them tend to have high boiling points.

5 0
3 years ago
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