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ValentinkaMS [17]
4 years ago
8

I only need answer to question number 10. please help me.

Mathematics
2 answers:
castortr0y [4]4 years ago
8 0

Answer:

2(4X-1) (4x-1)

Step-by-step explanation:

o-na [289]4 years ago
7 0

Answer:

2(4x−1)(4x−1)

Step-by-step explanation:

first you find the GCF of all of the terms, which is 2 because 32, 16, and 2 are all divisible by 2. Then you are left with 2(16n^2-8n+1). Now you factor the rest of it and you are left with 2(4x−1)(4x−1)

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Otero translated the phrase “three less than a number” into the expression 3-x. Which best describes the accuracy of Otero’s exp
xz_007 [3.2K]

Answer:

Option B is correct.

Step-by-step explanation:

Otero translated the phrase "three less than a number" into the expression 3 - x.

I think Otero gave a wrong expression for the phrase.

The true interpretation of the phrase is that if we assume the number as x then three less than a number means x - 3.

Therefore, Otero's expression is inaccurate. Three is being subtracted from a number, so x-3 is what he should have written. (Answer)

7 0
3 years ago
Read 2 more answers
Here is another one
ankoles [38]

Robin's Nest is K

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5 0
4 years ago
4.)list and discuss the various clues that flames and smoke can offer the investigator in the arson investigation.
Llana [10]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Gabrielle is traveling to Mexico and needs to exchange $440 into Mexican pesos. If each dollar is worth 11.84 pesos, how many pe
alexira [117]

Answer:

5209.60 pesos

Step-by-step explanation:

$440 x 11.84= 5209.60

6 0
3 years ago
Renee scores an average of 153 points in a game of bowling, and her points in a game of bowling are normally distributed. Suppos
Lelu [443]

Answer:

\sigma=\frac{175-153}{2}=11

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent points in a game of bowling of a population, and for this case we know the distribution for X is given by:

X \sim N(153,unknown)  

Where \mu=153 and \sigma=?

We know that the value for Renee is X=175 and the z score obteined was Z=2.

Solution to the problem

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{X-\mu}{\sigma}

We are interested on the value of \sigma and we can solv for it:

z \sigma = X-\mu

\sigma=\frac{X-\mu}{z}

And replacing the values we have:

\sigma=\frac{175-153}{2}=11

 

5 0
3 years ago
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