Answer:
angle V = 60 degrees
angle U = 90 degrees
angle W = 30 degrees
This is the last option
Explanation:
Part a: getting angle U:
Let's start by doing the Pythagorean check:
hypotenuse = sqrt [(side1)^2 + (side2)^2]
side1 = 3√3 and side2 = 3 cm
Substitute in the above equation:
hypotenuse = sqrt [ (3√3)^2 + (3)^2]
hypotenuse = 6 cm
This proves that the given triangle is right-angled at U
Therefore:
measure angle U = 90 degree
Part b: getting angle V:
cos theta = adjacent / hypotenuse
theta is angle V
adjacent side = 3 cm
hypotenuse = 6 cm
Therefore:
cos V = 3/6 = 1/2
V = 60 degrees
Part c: getting angle W:
We can get this using two methods:
Method 1:
Angles of triangle = 180
180 = 90 + 60 + angle W
angle W = 180 - (90+60) = 30 degrees
Method 2:
cos theta = adjacent / hypotenuse
theta is W
adjacent = 3√3 cm
hypotenuse = 6 cm
Therefore:
cos W = 3√3 / 6 = √3 / 2
W = 30 degrees
Hope this helps :)
The first is not a polynomial as one term is dividing.
(5, 9), (5, -2)
x1 y1 x2 y2
Plug in what we know:
Subtract:
We can't divide by zero, so:
Answer:
2.530 kg
Step-by-step explanation:
230g = 0.23 kg
2.3+0.23=2.53kg
Answer:
x = - 8 and (- 8, 0 )
Step-by-step explanation:
Given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the equation of the axis of symmetry which is also the x- coordinate of the vertex is
x = - 
y = x² + 16x + 64 ← is in standard form, with
a = 1 and b = 16, then
x = - 
= - 8
Equation of axis of symmetry is x = - 8
Substitute x = - 8 into the quadratic and evaluate for y
y = (- 8)² + 16(- 8) + 64 = 64 - 128 + 64 = 0
vertex = (- 8, 0 )
