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vichka [17]
4 years ago
15

If someone can help me understand, and figure this problem. . If each substance costs the same amount per kilogram (kg), which w

ould be most cost-effective as a way to lower the freezing point of water? (Assume complete dissociation for all ionic compounds.) Explain. Ill post the 5 molecules as a drawing.
Chemistry
2 answers:
kompoz [17]4 years ago
8 0
The most <span>cost-effective as a way to lower the freezing point of water is SrCl2 because it will form three ions in the solution. The more ions are there in the solution, the more water molecules will be unable to get out of the solution since it is trapped by the ions of the SrCl2. It would not depend on the nature of the substance no matter how heavy or light it is as long as the dissociation of ions in the solution is many then it is enough.</span>
sleet_krkn [62]4 years ago
4 0

NaCl would be the most cost-effective as a way to lower the freezing point of water. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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2. How many moles of hydrogen atoms are there in 154 mL of 0.18 M H2SO4? Write your
katrin [286]

2. 0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. 15.2506 heat in Joules is absorbed by 150.0 mL of pure water that is heated from 21.2°C to  45.5°C.

4. 0.75 M is the concentration of Na+ ions in 25.0 mL of 1.50 M NaOH is reacted with 25.0 mL of  1.50 M HCI

Explanation:

Number of moles of H2SO4 can be calculated by the given volume and molarity from the formula:

molarity = \frac{number of moles}{volume of teh solution}

number of moles = molarity × volume of the solution of H2SO4

    number of moles = 0.18 × 0.154 litres

                                   = 0.02772 moles of H2SO4.

Since 1 mole of H2SO4 contains 2 moles of hydrogen

so, 0.02772 moles of H2SO4 will have x moles

\frac{1}{2} = \frac{0.0272}{x}

2 × 0.02772 = x

0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. The heat absorbed is calculated from the formula:

ΔH = cp × m × ΔT   ( ΔT = change in temperature in Kelvin, m in kg, cp= specific heat of water)

putting the values in formula:

ΔH = 4.184 × 0.15 × ( 318.65-294.35)

     =  4.184 × 0.15× 24.3

        = 15.2506 Joules of heat is absorbed.

4. The concentration of Na+ ions

the balanced equation is

NaOH + HCl⇒ NaCl + H20

from one mole of NaCl 1 mole of NaCl i.e one 1 mole of Na+ ions is formed.

number of moles of NaOH is calculated by the formula:

Molarity = \frac{number of moles}{volume of the solution}

number of moles = 0.025L × 1.50M

                             = 0.0375 moles of NaOH

so 1 mole of NaOH produces 1 mole of Na= ions

hence, 0.0375 moles produces x moles of Na+ ions

\frac{1}{1} = \frac{0.0375}{x}

moles of Na+ is produced.  

concentration of NaOH in 50 ml solution because NaOH and HCl of 25 ml reacted.

applying the molarity formula from above

Molarity =  \frac{0.0375}{0.05}

              =  0.75 M

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