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vichka [17]
4 years ago
15

If someone can help me understand, and figure this problem. . If each substance costs the same amount per kilogram (kg), which w

ould be most cost-effective as a way to lower the freezing point of water? (Assume complete dissociation for all ionic compounds.) Explain. Ill post the 5 molecules as a drawing.
Chemistry
2 answers:
kompoz [17]4 years ago
8 0
The most <span>cost-effective as a way to lower the freezing point of water is SrCl2 because it will form three ions in the solution. The more ions are there in the solution, the more water molecules will be unable to get out of the solution since it is trapped by the ions of the SrCl2. It would not depend on the nature of the substance no matter how heavy or light it is as long as the dissociation of ions in the solution is many then it is enough.</span>
sleet_krkn [62]4 years ago
4 0

NaCl would be the most cost-effective as a way to lower the freezing point of water. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Imagine that Ana has a block made of pure gold. If she cuts this block into two equal pieces, pick the statement that best descr
dimaraw [331]

Answer : The correct statement is:

The density of each piece is the same as that of the original block.

Explanation :

Intensive property : It is defined as a property of substance which does not change as the amount of substance changes.

Examples: Temperature, refractive index, density, hardness, etc.

According to question, if Ana has a block made of pure gold and she cuts this block into two equal pieces then the density of each piece is the same as that of the original block because density is an intensive property that does not changes until and unless material is changed.

That means density remains same as that of the original piece.

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If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial
Tems11 [23]

Answer:

0.0295M

Explanation:

As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.

You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.

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0.0800M / 2.714 =

<h3>0.0295M </h3>

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ACFrOgDjZVP5d1mO2l6HAtPZQNnbFRq674g04E7uZadqJMPc4VbhdTIEDCWBeh3xfw9BrKkfHHEN4nxe9NVglsb9N8D49CjxvxHYw3L93m4wO6SY5SwKQYMk-2zzHtGz
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Mamont248 [21]

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