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3 years ago

What is the first quartile of the following data set?

Chemistry

1 answer:

Darina [25.2K]3 years ago

6 0

Answer:

hdhhdhhdhgdgdvsgsvsvvsvsvsvsvs

Explanation:

hdhbdbdbdbdbdbxbxbxvxbxbbxbxvxvxvxv

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What is mass in g of 15.5 moles of calcium?

padilas [110]

Answer:

621.2090000000001 grams

Explanation:

1 moles Calcium to grams = 40.078 grams

15.5*40.078 = 621.2090000000001 g

4 0

3 years ago

How many grams are in 10 moles of methane, CH4?

ollegr [7]

the answer is twenty eight

6 0

3 years ago

Read 2 more answers

Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid with water

Vera_Pavlovna [14]

Answer:

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3 years ago

Which pair of molecules is expected to have the most different properties?

Artyom0805 [142]

Answer:

This question is incomplete

The completed question is below

Which pair of molecules is expected to have the most different properties?

CO and NO

SO₂ and CH₄

The correct answer is SO₂ and CH₄

Explanation:

All the four substances are gases at room temperature.

Carbon monoxide (CO) and nitric oxide (NO) are both reactive oxides. They are both polar and inorganic also, hence should have some similar properties (based on there origin/composition and polarity).

Sulphur dioxide (SO₂) is polar because it's a bent molecule, methane (CH₄) is non-polar because of the tetrahedral shape of it's molecule. Methane is an organic molecule while sulphur dioxide is an inorganic molecule.

From the above, it can be deduced that SO₂ and CH₄ are expected to have different properties. For example, the polarity of SO₂ makes it dissolve in water to form an acidic solution while methane does not dissolve in water and hence doesn't form an acidic solution.

5 0

3 years ago

Ammonia is formed according to the reaction below. A chemist mixes 21 grams of nitrogen gas and 18 grams of hydrogen gas in a 2.

Rama09 [41]

Answer : The mass of hydrogen gas consumed will be, 4.5 grams

Explanation : Given,

Mass of $N_2$ = 21 g

Mass of $H_2$ = 18 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $H_2$ = 2 g/mole

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{21g}{28g/mole}=0.75moles$

$\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{18g}{2g/mole}=9moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given balanced reaction, we conclude that

As, 1 mole of $N_2$ react with 3 moles of $H_2$

So, 0.75 moles of $N_2$ react with $3\times 0.75=2.25$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent because it limits the formation of product.

The moles of hydrogen gas consumed = 2.25 mole

Now we have to calculate the mass of hydrogen gas consumed.

$\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2$

$\text{Mass of }H_2=(2.25mole)\times (2g/mole)=4.5g$

Therefore, the mass of hydrogen gas consumed will be, 4.5 grams

5 0

3 years ago