Answer:
455.4 mmHg
Explanation:
To solve this problem we can use <em>Gay Lussac's Law</em>, which describe the temperature and pressure of a gas, at constant volume and composition:
In this case:
We <u>input the data</u>:
- 621 mmHg * 231 K = P₂ * 315 K
And <u>solve for P₂</u>:
A. represents a situation in which the person is not handling frustration well. In the other situations, the people found they weren't doing as well as they had hoped and so they actively found ways to maneuver around this to improve their lives. Leslie gave up her job simply the move back with her parents with no indication that she would be able to support herself until she got the job she wanted. It's important to keep a source on income while chasing down a dream job.
Hope this helps! :)
Competition is most likely to occur between two organisms. When the organisms interfere with each others resource or when organisms interfere with each others reproduction which will cause the others life to be in short or danger.
Answer:
the partial of colloidal are smaller and they are not heavy whereas the partial of suspension are larger but they are heavy and less movement thus they settle down due to gravity
Answer:
(a) 13.7 g.
(b) 28.91 g.
Explanation:
- molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.
∴ m = (no. of moles of solute)/(mass of water (kg))
<em>∴ m = (mass/molar mass of solute)/(mass of water (kg)).</em>
<em />
<u><em>(a) Calculate the mass of CaCl₂·6H₂O needed to prepare 0.125 m CaCl₂(aq) by using 500. g of water.</em></u>
∵ m = (mass/molar mass of CaCl₂·6H₂O)/(mass of water (kg)).
m = 0.125 m, molar mass of CaCl₂·6H₂O = 219.0757 g/mol, mass of water = 500.0 g = 0.5 kg.
∴ 0.125 m = (mass of CaCl₂·6H₂O / 219.0757 g/mol)/(0.5 kg).
∴ mass of CaCl₂·6H₂O = (0.125 m)(219.0757 g/mol)(0.5 kg) = 13.7 g.
<u><em>(b) What mass of NiSO₄·6H₂O must be dissolved in 500. g of water to produce 0.22 m NiSO₄(aq)?</em></u>
∵ m = (mass/molar mass of NiSO₄·6H₂O)/(mass of water (kg)).
m = 0.22 m, molar mass of NiSO₄·6H₂O = 262.84 g/mol, mass of water = 500.0 g = 0.5 kg.
∴ 0.125 m = (mass of NiSO₄·6H₂O / 262.84 g/mol)/(0.5 kg).
∴ mass of NiSO₄·6H₂O = (0.22 m)(262.84 g/mol)(0.5 kg) = 28.91 g.
