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Bumek [7]
3 years ago
15

Discuss risks associated with people in cyber threat

Computers and Technology
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

1. Hacking of personal details.

2. Cyber harassment.

3. Hacking of business details.

Moreover it is a mental trauma for the victim too

Explanation:

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I don’t really understand what you are trying to ask. Try posting a picture along with your question
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Good participation in music is strictly limited to those who perform well. true or false
sdas [7]
The answer would be false because you don't have to be good at it to participate and try your hardest
8 0
3 years ago
Read 2 more answers
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
4 years ago
write a c++ program that reads from the user a positive integer (in a decimal representation), and prints its binary (base 2) re
Vesna [10]

Answer:

The program to this question can be described as follows:

Program:

#include <iostream> //defining header file

using namespace std;

int main() //defining main method

{

int x1,rem,i=1; //defining integer variable

long Num=0;// defining long variable

cout << "Input a decimal number: "; // print message

cin >> x1; //input value by user

while (x1!=0) //loop for calculate binary number

{

//calculating binary value    

rem= x1%2;

x1=x1/2;

Num =Num +rem*i;//holding calculate value

i=i*10;

}

cout <<Num;//print value

return 0;

}

Output:

Input a decimal number: 76

1001100

Explanation:

In the above code, four variable "x1, rem, i, and Num" is declared, in which three "x1, rem, and i" is an integer variable, and one "Num" is a long variable.

  • In the x1 variable, we take input by the user and use the while loop to calculate its binary number.
  • In the loop, first, we check x1 variable value is not equal to 0, inside we calculate it binary number that store in long "Num" variable, after calculating its binary number the print method "cout" is used to prints its value.  
5 0
3 years ago
The input nums is supposed to be an array of unique integers ranging from 1 to nums.length (inclusive). However, there is a mist
Elden [556K]

The program is an illustration of loops.

Loops are used to perform repetitive and iterative operations.

The program in Python where comments are used to explain each line is as follows:

#This intializes the list

nums = [5,4,4,2,1]

#This gets the length of the list

size = len(nums)

#This iterates through the list

for i in range(size):

   #The following if condition determines the repeating number

   if nums[abs(nums[i])-1] > 0:

       nums[abs(nums[i])-1] = -nums[abs(nums[i])-1]

   else:

       repeating = abs(nums[i])

   #The following if condition determines the missing number

   if nums[i]>0:

       missing = i + 1

   

#This calculates and prints the sum of the missing and the repeating numbers

print(repeating+missing)

Read more about similar programs at:

brainly.com/question/13549861

6 0
3 years ago
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