1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tankabanditka [31]
3 years ago
11

Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e

nd of a symmetric object, such as a rectangular block with uniform mass density. In this case, with the springs next to each other, we describe them as being in parallel. Find the effective spring constant of the pair of springs as a system in this situation in terms of k3. (Use the following as necessary: k3, M, the mass of the symmetric object, and g, the gravitational acceleration.)
Physics
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

 Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

                F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

          F + F = m a

         k₃ x + k₃ x = m a

         a = 2k₃  x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

       Keq = 2k₃

You might be interested in
Which of the following is not an essential feature of scientific explanations?
sineoko [7]

Answer:

D I think I might be wrong its been a while scense I did something like that

4 0
3 years ago
A particle travels in a circle of radius 76 cm and completes one revolution in 4.5 s. What is the centripetal acceleration of th
Dimas [21]

r = radius of the circle traveled by the particle = 76 cm = 0.76 m

T = time period of revolution for the particle = 4.5 s

w = angular velocity of the particle

angular velocity of the particle is given as

w = 2π/T

inserting the values

w = 2 (3.14)/4.5

w = 1.4 rad/s

a = centripetal acceleration of the particle in the circle

centripetal acceleration is given as

a = r w²

inserting the values

a = (0.76) (1.4)²

a = 1.5 m/s²

3 0
3 years ago
Read 2 more answers
2.What is the weight of an object that has a mass of 5 kg?<br>​
Artemon [7]

Answer:

5 kg

or 11 lbs

Explanation:

4 0
3 years ago
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d
galben [10]
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists describe as elliptical. It is one of Kepler's laws. The sun is the focus of all the planets. The correct answer is D.
7 0
4 years ago
What is the highest degrees above the horizon the moon ever gets during the year in the Yakima Valley ?
Ivahew [28]

The trickiest part of this problem was making sure where the Yakima Valley is.
OK so it's generally around the city of the same name in Washington State.

Just for a place to work with, I picked the Yakima Valley Junior College, at the
corner of W Nob Hill Blvd and S16th Ave in Yakima.  The latitude in the middle
of that intersection is 46.585° North.  <u>That's</u> the number we need.

Here's how I would do it:

-- The altitude of the due-south point on the celestial equator is always
(90° - latitude), no matter what the date or time of day.

-- The highest above the celestial equator that the ecliptic ever gets
is about 23.5°. 

-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
that's the highest above the ecliptic that the moon can ever appear
in the sky.

This sets the limit of the highest in the sky that the moon can ever appear.

90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .

That doesn't happen regularly.  It would depend on everything coming
together at the same time ... the moon happens to be at the point in its
orbit that's 5.14° above ==> (the point on the ecliptic that's 23.5° above
the celestial equator).

Depending on the time of year, that can be any time of the day or night.

The most striking combination is at midnight, within a day or two of the
Winter solstice, when the moon happens to be full.

In general, the Full Moon closest to the Winter solstice is going to be
the moon highest in the sky.  Then it's going to be somewhere near
67° above the horizon at midnight.


5 0
3 years ago
Other questions:
  • Why is friction important for gymnast working on parallel bars
    12·1 answer
  • How many changes of state are shown?<br> 0<br> 1<br> 2<br> 3
    13·2 answers
  • The troughs or zero amplitude of a standing wave are called ____________.
    10·1 answer
  • An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su
    5·1 answer
  • Which of these would have particles with the highest kinetic energy? Ice Water Water Vapor
    5·2 answers
  • What makes the id different from the superego?
    10·1 answer
  • HELP PLEASEE ILL GIVE BRAINLIEST
    6·1 answer
  • The girl in the diagram is accelerating down the hill, What is the girl’s acceleration.
    6·2 answers
  • The speed of a star, can you measure it? Is it constant?
    7·1 answer
  • The velocity of a bus increases from 27km/h to 30m/s in . Calculate its acceleration.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!