Pnet = Po + dgh
<span>Density of saltwater = 1030 kg/m^3. </span>
<span>Disregard the thickness. Assuming it's a circular window, then the area is pi(r^2). </span>
<span>d = 20 cm = 0.2 m </span>
<span>r = d/2 = 0.1 m </span>
<span>A = pi(r^2) </span>
<span>A = 3.14159265(.1^2) </span>
<span>A = 0.0314159265 m^2 </span>
<span>p = F/A </span>
<span>p = (1.1 x 10^6) / (0.0314159265) </span>
<span>p = 35,014,087.5 Pa </span>
<span>1 atm = 101,325 Pa </span>
<span>P = Po + dgh </span>
<span>h = (P - Po) / dg </span>
<span>h = (35,014,087.5 - 101,325) / (1030 x 9.81) </span>
<span>h = 3 455.23812 m </span>
<span>h = 3.5 km</span>
I believe the term Frequency is what you are looking for.
To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to
The ideal gas equation said us that,
PV = nRT
Here,
P = pressure
V = Volume
R = Gas ideal constant
T = Temperature
n = Amount of substance (at this case the mass)
Then
The amount of substance per volume is the density, then
Replacing with our values,
Finally the specific volume would be
Answer:
Explanation:
Examples are;
Ultraviolet light from sun.
Heat from a stove burner.
X-ray from an x-ray machine.
Alpha particle emit from a radio active decay of uranium.
Sound waves from your stereo.
Microwave from micro oven.
ultraviolet light from a black light.
Gamma radiations from a supernova.
AND MANY MORE.
