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ziro4ka [17]
3 years ago
9

A circuit is constructed with six resistors and two batteries as shown. the battery voltages are v1 = 18 v and v2 = 12 v. the po

sitive terminals are indicated with a + sign, the values for the resistors are: r1 = r5 = 58 Ï, r2 = r6 = 124 Ï r3 = 47 Ï, and r4 = 125 Ï. the positive directions for the currents i1, i2 and i3 are indicated by the directions of the arrows. 1) what is v4, the magnitude of the voltage across the resistor r4?
Physics
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

V4=9.197v

Explanation:

Given:

V1= 18v ,V2= 12v ,r1=r5=58ohms ,r2=r6=124ohms , r3=47ohms ,r4= 125ohms

V4= I4R4 = V2/(R4 + R5)×R4

V4= 12×125 /(125 + 58)

V4=1500/183 =9.197v

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Using both equation and solving for the modulus of elasticity E

E = бx/ex = Fx / πr^{2}ex

E = \frac{15}{pi (10 * 10^{-3})^{2} * 2.75 * 10^{-6}    } = 17.368 * 10^{9} Pa = 17.4 GPa

Apply the Hooke's law for either y or z direction (circle will change in every direction) we can find the change in radius

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Δd = 2Δr = -12.6 * 10^{-6} mm

Explanation:

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