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2 years ago

The expected value of a random variable is the

Mathematics

1 answer:

alekssr [168]2 years ago

6 0

Answer:

The expected value of random variable X is often written as E(X) or µ or µX.

Step-by-step explanation:The expected value is the 'long-run mean' in the sense that, if as more and more values of the random variable were collected (by sampling or by repeated trials of a probability activity), the sample mean becomes closer to the expected value.

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Every set of three points must be collinear.

maria [59]

Answer:

I suppose you're trying to make a triangle of some sort on a plane! So, in this case, yes the three points would reside all on the same plane. Making all three of them collinear.

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2 years ago

Which of the following expressions is not correctly written in scientific notation?

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2 years ago

Read 2 more answers

An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a

MAVERICK [17]

Answer:

Probability Mass Function:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

$P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064$

$P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608$

$P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902$

$P(x = 3)\\= \binom{3}{3}(0.96)^3(1-0.96)^0\\=0.884736$

PMF:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

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2 years ago

Can you help me understand front end and clusters when u round

Galina-37 [17]

Answer:

I really hope this help! Some may call it front end rounding while others call is front end estimating, even though they mean the same thing. When rounding a place value, you need to look to the number to the right of it. Example: Most often a teacher may as you round the number 452 to the nearest ten’s. That number will than be 450. But why? Well as we look at the number, we know we need to round to the nearest ten. So in our case it would be 52. Our rule to remember when rounding is 5 and higher we round-up. Since we are looking at the portion of the number 52, we go right of the tens place to find the number 2. Since the number 2 is not 5 or higher, we round down making it 50. Don’t forget to finish the problem by adding the hundreds back to the original number. Your answer for this problem is 450.

Step-by-step explanation: I really hope this helps i will post the rest in the comment!

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3 years ago