You are given two objects of identical size, one made of aluminum and the other of lead. You hang each object separately from a
1 answer:
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Answers:
(a)
μT
(b)
μm
(c) f =
Explanation:
Given electric field(in y direction) equation:
(a) The amplitude of electric field is
. Hence
The amplitude of magnetic field oscillations is
Where c = speed of light
Therefore,
μT (Where T is in seconds--signifies the oscillations)
(b) To find the wavelength use:
μm
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
(a)
(b)
(c) f =
Explanation:
Given electric field(in y direction) equation:
(a) The amplitude of electric field is
The amplitude of magnetic field oscillations is
Where c = speed of light
Therefore,
(b) To find the wavelength use:
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
Answer:
Rs = 0.02008 Ω = 20.08 mΩ
Explanation:
The range of an ammeter can be increased by connecting a small shunt resistance to it in a series combination. This shunt resistance can be calculated by the following formula:
where,
= value of shunt resistance = ?
= current range of ammeter = 20 mA = 0.02 A
I = Required range of ammeter = 5 A
= Resistance of ammeter = 5 ohms
Therefore,
<u>Rs = 0.02008 Ω = 20.08 mΩ</u>