The acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².
Answer:
Explanation:
Acceleration exerted by any object in order of decrease in the speed is termed as deceleration. In other words , negative acceleration or acceleration acting in opposite direction to stop the motion of any object is termed as deceleration. The magnitude of acceleration and deceleration is same only the direction is completely opposite to each other. So the negative sign will be obtained for acceleration value of any object whose velocity slows down from initial velocity.
Here , the initial velocity was 60 m/s and the final velocity is slowed down to 40 m/s in time 10 s.
So acceleration = (Final velocity - Initial velocty)/Time
Acceleration = (40-60)/10 = -20/10 = -2 m/s².
Thus, the acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².
Answer:
q=6.22*10^-10C
Explanation:
Two large metal plates of area 0.88 m2 face each other, 4.8 cm apart, with equal charge magnitudes but opposite signs. The field magnitude E between them (neglect fringing) is 80 N/C. Find |q|
E=α/∈, electric field within the plate
α=q/A
A=area of the plate
∈=is the permittivity
substituting , we have
The field magnitude E between them (neglect fringing)
E=q/A∈
q=EA∈
q=0.88*80*8.84*10^-12
q=6.22*10^-10C
Answer:
each rotation of the smaller wheel will show 84.382-75.3982=8.9838 inches more than the actual distance
Explanation:
d = Diameter of the wheel
The distance traveled in one rotation of the wheel is the circumference of the wheel
When diameter is 24 inches
Therefore, each rotation of the smaller wheel will show 84.382-75.3982=8.9838 inches more than the actual distance
If the friction increase it would make the thing sliding down slower and makes heat
