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fenix001 [56]
3 years ago
6

A scientist travelled 80 kilometres each day in the buggy.

Physics
2 answers:
Pani-rosa [81]3 years ago
5 0
Multiply 80 x 10 which is a total of 800
7nadin3 [17]3 years ago
4 0

Explanation:

In one day a scientist can travel = 80 km

In 10 days. a scientist can travel = 80* 10

= 800 km.

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A light bulb is connected to a 2V supply and experiences a current of 6.4A. What is the power rating of the bulb?
Olenka [21]

Answer:

12.8 Watts

Explanation:

P = VI

P = (2 V) (6.4 A)

P = 12.8 W

8 0
3 years ago
For a 50 kV anode voltage, what is the maximum photon energy of the x-ray radiation?
V125BC [204]

Answer:

The energy of photon, E=8\times 10^{-15}\ J

Explanation:

It is given that,

Voltage of anode, V=50\ kV=50\times 10^3\ V=5\times 10^4\ V

We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.

E=eV

e is charge of electron

E=1.6\times 10^{-19}\times 5\times 10^4

E=8\times 10^{-15}\ J

So, the maximum energy of the x- ray radiation is 8\times 10^{-15}\ J. Hence, this is the required solution.

6 0
3 years ago
Use the following words to complete the passage: add, reflecting, light, reflect, cancel, white, colors, waves interference, bri
Yuri [45]
1. white
2. colors
3. reflecting
4. light
5. waves interferences
6. reflect
7. add
8. brighter
9. cancel
6 0
3 years ago
In physics 28.97 + 45.876 adds up to what?
myrzilka [38]

28.97 + 45.876

equals 74.846

6 0
3 years ago
Read 2 more answers
A straight segment of wire has a length of 25 cm and carries a current of 5A. If the wire is perpendicular to the magnetic field
Irina-Kira [14]

Answer:

The magnitude of the magnetic force acting on the conductor is 0.75 Newton

Explanation:

The parameters given in the question are;

The length of the straight segment of wire, L = 25 cm = 0.25 m

The current carried in the wire, I = 5 A

The orientation of the wire with the magnetic field = Perpendicular

The strength of the magnetic field in which the wire is located, B = 0.60 T

The magnetic force, 'F', is given by the following formula;

F = \underset{I}{\rightarrow }·L×\underset{B}{\rightarrow } = I·L·B·sin(θ)

Where;

\underset{I}{\rightarrow } = The current flowing, I

L = The length of the wire

\underset{B}{\rightarrow } = The magnetic field strength, B

θ = The angle of inclination of the conductor to the magnetic field

Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;

F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N

Therefore

The magnitude of the magnetic force, F = 0.75 N.

3 0
3 years ago
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