The work done by the electric field in moving a charge is the negative of the potential energy difference between the two locations, which is the product between the magnitude of the charge q and the potential difference

:

The proton charge is

, and the two locations have potential of

and

, therefore the work is
Answer:
t=2s
Explanation:
The definition of power is:

And the work-energy theorem states that:

Since the movement starts from rest, we have that:

And putting all together:

Since we want the time taken:

Which for our values is:

the answer is B- are renewable resources
A “real” image occurs when light rays actually intersect at the image, and become inverted, or turned upside down. ... In flat, or plane mirrors, the image is a virtual image, and is the same distance behind the mirror as the object is in front of the mirror. The image is also the same size as the object.