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zhenek [66]
3 years ago
8

Cody is using a sling shot and rock to knock down a can that he has placed on a tree stump. His first attempt fails because he r

ealizes the rock didn't go far enough. How does Cody increase the amount of potential energy of the rock to make it reach the can and knock it down?
A. Cody needs to stretch the sling shot back more.


B. Cody needs to get a bigger rock.


C. There is no way that Cody can knock the can down.
Physics
2 answers:
Archy [21]3 years ago
3 0

it is believed to be the letter a

Hunter-Best [27]3 years ago
3 0

Answer:

c or a Hope's that helps but I think it's c

Explanation:

byeeeee

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It has been a hot summer, so when you arrive at a lake, you decide to go for a swim even though it is nighttime. The water is co
ale4655 [162]

Answer: This is because water has a higher Specific Heat Capacity than air.

Explanation:

The specific heat capacity of an object measures how much heat will be required to change its temperature.

Water has a higher specific heat capacity than air, so the temperature of the water will remain fairly constant even though the air surrounding the water is experience temperature changes.

Since air has a lower Specific Heat Capacity than water, heat from the sun will readily heat it up in comparison to water.

6 0
4 years ago
Compared to wave A, wave B has a _____. (1 point) longer wavelength and lower frequency longer wavelength and lower frequency lo
pshichka [43]

Answer:

longer wavelength and lower frequency

shorter wavelength and greater frequency

Explanation:

f = v/l

l = wavelength

v = speed of wave

f = frequency

7 0
3 years ago
D. What is the net force on the bowling ball rolling lane
3241004551 [841]

Answer:

Friction

Explanation:

3 0
3 years ago
Light of wavelength 550 nm falls on a
Brums [2.3K]

Answer:

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

a\sin\theta=m\lambda (1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum (y_{m}) are small compared to the distance between the screen and the slit (x), we can approximate \sin\theta\approx\tan\theta=\frac{y}{x}, using this on (1):

a\frac{y_{m}}{x}=m\lambda

solving for y

y_{m}= \frac{mx\lambda}{a}

Note that y_{m}is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find y_{1}, y_{2} add them and divide by two:

y_{1}= \frac{(1)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}

y_{1}= 1.8 m

y_{2}= \frac{(2)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}

y_{1}= 3.6 m

maximum = \frac{1.8+3.6}{2}=2.7m

7 0
3 years ago
Consider the vector b⃗ with magnitude 4.00 m at an angle 23.5∘ north of east. what is the x component bx of this vector?
Aleksandr [31]

Answer:

3.67 m

Explanation:

A physical quantity is said to be vector quantity if it need a magnitude as well as direction for complete explanation.

It makes an angle 23.5 degree from positive X axis.

So, it's component along X axis is given by

bx = B Cos theta

bx = 4 × Cos 23.5

bx = 3.67 m

6 0
4 years ago
Read 2 more answers
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