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omeli [17]
3 years ago
14

A bicycle odometer which counts revolutions and is calibrated to report distance traveled is attached near the wheel axle and is

calibrated for 27 inches wheel what happens if you use it on a bicycle with 24 inches wheels?
Physics
1 answer:
Bess [88]3 years ago
6 0

Answer:

each rotation of the smaller wheel will show 84.382-75.3982=8.9838 inches more than the actual distance

Explanation:

d = Diameter of the wheel

The distance traveled in one rotation of the wheel is the circumference of the wheel

\pi d=\pi\times 27\\ =84.823\ inch

When diameter is 24 inches

\pi d=\pi\times 24\\ =75.3982\ inch

Therefore, each rotation of the smaller wheel will show 84.382-75.3982=8.9838 inches more than the actual distance

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Help??? Phases of the moon. Am I right
Ksenya-84 [330]

Answer:

Yes. You are correct. Great job!

Explanation:

4 0
4 years ago
A type of Lead (Pb) ion has a + 4 oxidation number. Sulfur (S) has a — 2 oxidation number. What would be the chemical formula fo
serious [3.7K]

Answer: The chemical formula for the compound of these two elements is PbS_2

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here metal lead is having an oxidation state of +4 called as Pb^{4+} cation and sulphur non metal has oxidation state of -2 called as S^{2-}. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral PbS_2

The chemical formula for the compound of these two elements is PbS_2

4 0
3 years ago
A laser pulse with wavelength 532 nm contains 3.85 mj of energy. how many photons are in the laser pulse?
erastovalidia [21]

Answer:<em> </em><em>1.04 × 10¹⁶ photons</em>


Explanation:


1) Data:

  • E = 3.85mJj (mili joules) = 3.85×10⁻³ J
  • λ = 532 nm = 532 × 10⁻⁹ m
  • number of photons ?

2) Physical principles

a) The energy of a photon is given by the equation E = hν.

Where:

  • h is Planck's constant 6.62607004 × 10⁻³⁴ J×s
  • ν is the freguency of the light

b) The wavelength, λ, and the frequency, are related by the equation:

  • ν = c / λ, where c is the speed of light at vacuum, approximately 3.0 × 10⁸ m/s

3) Solution:

  • ν = c / λ = 3.0 × 10⁸ m/s / (538 nm) × 10⁹ nm/m = 5.576×10¹⁴ Hz

  • E = hν = 6.62607004 × 10⁻³⁴ J×s s × 5.576×10¹⁴ Hz = 3.69 × 10 ⁻¹⁹ J

  • Divide the total energy by the energy of one photon to find the number of photons:

         3.85×10⁻³ J / 3.69 × 10 ⁻¹⁹ J-photon = 1.04 × 10¹⁶ photons ← answer


4 0
3 years ago
Read 2 more answers
A mass of 0.40 kg is suspended on a spring which then stretches 10 cm. The mass is then removed and a second mass is placed on t
Vanyuwa [196]

Answer:

 x' = 1.01 m

Explanation:

given,

mass suspended on the spring, m = 0.40 Kg

stretches to distance, x = 10 cm  = 0. 1 m

now,

we know

m g = k x

where k is spring constant

0.4 x 9.8 = k x 0.1

  k = 39.2 N/m

now, when second mass is attached to the spring work is equal to 20 J

work done by the spring is equal to

W = \dfrac{1}{2}kx'^2

20= \dfrac{1}{2}\times 39.2\times x'^2

 x'² = 1.0204

 x' = 1.01 m

hence, the spring is stretched to 1.01 m from the second mass.

 

7 0
3 years ago
Throw a paper ball towards a hard wall.
Len [333]
The answer is d hope this helps
7 0
3 years ago
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