1.16 g of UF₄ can be formed in this reaction.
<u>Explanation:</u>
We have to write the balanced equation of the reaction between Uranium oxide and hydrogen fluoride to form Uranium tetra fluoride and water as,
UO₂(s) +4 HF(aq) → UF₄ + 4 H₂O(l)
We can find the moles of UF₄ and then multiplying molar mass of UF₄ with the moles of UF₄, we will get the mass of UF₄ in grams.
Moles of UF₄ = 
= 0.00370 mol UF₄
Grams of UF₄ =0.00370 mol × 314.02 g/mol = 1.16 g of UF₄
So mass of UF₄ formed in the reaction is 1.16 g.
Bsbdjxjxnamizizs brush’s ebeidhcycyudejej ehducudidksne r
The molecular mass of
is: 1·1 + 1·14.01 + 2·16 = 47.01 g/mol.
Now we can convert the mass into mol of
:
