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erastova [34]
4 years ago
13

Using the unbalanced reaction below:

Chemistry
1 answer:
Vladimir [108]4 years ago
5 0

1.16 g of UF₄ can be formed in this reaction.

<u>Explanation:</u>

We have to write the balanced equation of the reaction between Uranium oxide and hydrogen fluoride to form Uranium tetra fluoride and water as,

UO₂(s) +4 HF(aq) → UF₄ + 4 H₂O(l)

We can find the moles of UF₄ and then multiplying molar mass of UF₄ with the moles of UF₄, we will get the mass of UF₄ in grams.

Moles of UF₄ =   $  \frac{ 1 mol of UO_{2}\times 1 mol of UO_{2\times 1 mol of UF_{4} }  }{270.03 g \times 1 mol of UO_{2} }

                       = 0.00370 mol UF₄

Grams of UF₄ =0.00370 mol × 314.02 g/mol = 1.16 g of UF₄

So mass of UF₄ formed in the reaction is 1.16 g.

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