Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m
Answer:
6/2times500=1500
Explanation:
s = d/t which means speed equals distance divided by time.
Answer:
she added more force, she went down a hill with more friction.
Explanation:
either one of them
Answer:
she is going to be mad dude
The second law of motion states that: the acceleration of an object is dependent upon two variables: - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object
<h3>Meaning of Motion</h3>
Motion can be defined as the process of changing position willingly or due to a force applied.
Motion can be seen in different forms and types depending on the object.
In conclusion, The second law of motion is used to deduce the formula for acceleration.
Learn more about second law of motion: brainly.com/question/2009830
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