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arsen [322]
3 years ago
10

1 An ice cube has the following dimensions.

Physics
1 answer:
Pavel [41]3 years ago
7 0

Answer:

a)V=lbh

=5.5cm ×8.4cm×8.0cm

=369.6cm^3

b)Density=Mass/Volume

=340g/369.6cm^3

=0.92g/cm^3.

Explanation:

Looking at your question, I thing if the shape of an object you're measuring is square, the length of all its side must be the same. In my opinion, I think the values of the lbh in the question are of a rectangle, which makes more sense.

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Maksim231197 [3]

Answer:

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Explanation:

8 0
3 years ago
A racecar accelerates uniformly from 18.5 mil to 46.1 m/s in 2.47 seconds.
laiz [17]

Answer:

<em>The acceleration of the racecar is</em> \mathbf{11.17~m/s^2}

Explanation:

<u>Uniformly Accelerated Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

\displaystyle a=\frac{v_f-v_o}{t}

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

\displaystyle a=\frac{46.1-18.5}{2.47}

\displaystyle a=\frac{27.6}{2.47}

a = 11.17~m/s^2

The acceleration of the racecar is \mathbf{11.17~m/s^2}

5 0
3 years ago
Inattention hyperactivity and impulsivity are characteristics of
RSB [31]

Answer:

ADHD, also called attention-deficit disorder, is a behavior disorder, usually first diagnosed in childhood, that is characterized by inattention, impulsivity, and, in some cases, hyperactivity.

Explanation:

6 0
3 years ago
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Andrew [12]

Answer:

B

Explanation:

acceleration = change in speed / change in time

for 1, speed increases over time, so positive acceleration

for 3, speed decreases over time, so negative acceleration (or deceleration)

5 0
3 years ago
Read 2 more answers
On august 10, 1972, a large meteorite skipped across the atmosphere above the western united states and western canada, much lik
RUDIKE [14]
(a)
The velocity of the meteorite just before hitting the ground is:
v=20 km/s=20000 m/s
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
\Delta K =  \frac{1}{2}mv^2= \frac{1}{2}(3.4 \cdot 10^6 kg)(20000 m/s)^2=6.8 \cdot 10^{14}J

(b) 1 megaton of tnt is equal to 1 MT=4.2 \cdot 10^{15}J
To find to how many megatons the meteorite energy loss \Delta E
corresponds, we can set the following proportion
1 MT: 4.2 \cdot 10^{15}J=x: \Delta E
And so we find
x=  \frac{\Delta E}{4.2 \cdot 10^{15}J}  = \frac{6.8 \cdot 10^{14}J }{4.2 \cdot 10^{15}J} =0.162 MT
So, 0.162 megatons.

(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of \Delta E=0.162 MT=162 kT. So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
1:13 kT=x:162 kT
And so we find
x= \frac{162 kT}{13 kT}=12.46
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
7 0
4 years ago
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