Question

Each molecule of hemoglobin combines with four molecule of oxygen in order to transport oxygen throughout the body. It is observed that 1.51 g of hemoglobin combines with 2.30 mL of O 2 at 37 °C and 743 torr. What is the molar mass of hemoglobin?

Answer 1

Answer:

68325.8 g/mol

Explanation:

Given that:

Pressure = 743 torr

Temperature = 37 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (37 + 273.15) K = 310.15 K  

T = 310.15 K  

Volume = 2.30 mL = 0.00230 L ( 1 mL = 0.001 L)

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.364 L.torr/K.mol

Applying the equation as:

743 torr × 0.00230 L = n × 62.364 L.torr/K.mol  × 310.15 K  

⇒n = 8.84 × 10⁻⁵ moles

Since, given that:-

4 moles of oxygen gas is transferred by 1 mole of haemoglobin.

8.84 × 10⁻⁵ moles  of oxygen gas is transferred by 8.84 × 10⁻⁵/4 moles of haemoglobin.

Moles of haemoglobin = 2.21 × 10⁻⁵ moles

Mass = 1.51 g

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$2.21\times 10^{-5}\ mol= \frac{1.51\ g}{Molar\ mass}$

$Molar\ mass= 68325.8\ g/mol$