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3 years ago

If water was used to rinse the burette used to dispense the hydrochloric acid solution, how would this affect

Chemistry

1 answer:

Rufina [12.5K]3 years ago

7 0

Answer:

The concentration of hydrochloric acid would be estimated to be less.

Explanation:

This is because, the hydroxyl ions from water react with the hydrogen ions from the hydrochloric acid, hence decreasing the moles of hydrogen ions which lowers the acidic strength of Hydrochloric acid.

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kolbaska11 [484]

Answer: jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

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4 0

3 years ago

The second-order diffraction for a gold crystal is at an angle of 22.20o for X-rays of 154 pm. What is the spacing between the c

Alenkinab [10]

Answer: The spacing between the crystal planes is $4.07\times 10^{-10}m$

Explanation:

To calculate the spacing between the crystal planes, we use the equation given by Bragg, which is:

$n\lambda =2d\sin \theta$

where,

n = order of diffraction = 2

$\lambda$ = wavelength of the light = $154pm=1.54\times 10^{-10}m$ (Conversion factor: $1m=10^{12}pm$ )

d = spacing between the crystal planes = ?

$\theta$ = angle of diffraction = 22.20°

Putting values in above equation, we get:

$2\times 1.54\times 10^{-10}=2d\sin (22.20)\\\\d=\frac{2\times 1.54\times 10^{-10}}{2\times \sin (22.20)}\\\\d=4.07\times 10^{-10}m$

Hence, the spacing between the crystal planes is $4.07\times 10^{-10}m$

4 0

3 years ago

A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62

vesna_86 [32]

Answer: The concentration of $H_2SO_4$ is 0.234 M

Explanation:

According to the neutralization law,

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1$ = basicity $H_2SO_4$ = 2

$M_1$ = molarity of $H_2SO_4$ solution = ?

$V_1$ = volume of $H_2SO_4$ solution = 50.0 ml

$n_2$ = acidity of $NaOH$ = 1

$M_1$ = molarity of $NaOH$ solution = 0.375 M

$V_1$ = volume of $NaOH$ solution = 62.5 ml

Putting in the values we get:

$2\times M_1\times 50.0=1\times 0.375\times 62.5$

$M_1=0.234M$

Therefore concentration of $H_2SO_4$ is 0.234 M

6 0

3 years ago

Which is the net result of the proton-proton chain? 6 protons = 2 heliums + 3 positrons + 3 neutrinos + gamma rays 4 protons = 1

saveliy_v [14]

Answer: 5.125 neutrinos

Explanation:

8 0

3 years ago

__________ could be the formula of an alkene. a. c3h8 b. c2h8 c. c6h6 d. c3h6 e. c17h36

drek231 [11]

The general formula for alkenes is CnH2n, the formula with hydrogen count double the carbon count should be the correct formula for alkene and that is d. C3H6.

What are alkenes?

Alkenes, commonly known as olefins, are organic unsaturated hydrocarbons that have one or more carbon-carbon double bonds in their chemical structure and are composed of carbon and hydrogen atoms.

Alkenes are unsaturated hydrocarbons with a double bond between the carbon atoms. Carbon atoms are connected by at least one double bond. The general formula for alkenes is C n H 2n. Olefin is frequently substituted with alkenes. The word "olefin" comes from the Greek phrase "olefin gas," which denotes the production of oil.

Since, their general formula is CnH2n, the formula with hydrogen count double the carbon count should be the correct formula for alkene and that is d. C3H6.

To learn more about alkenes from the given link below,

brainly.com/question/27179090

#SPJ4

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1 year ago