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Talja [164]
3 years ago
13

What 2 properties make capillary action possible

Chemistry
1 answer:
Natali5045456 [20]3 years ago
7 0
Cohesion and adhesion
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Answer the following questions:
Burka [1]

Answer:

the melting point is the factor what what degrees fahrenheit a metal or other solid substance melts. the significance of knowing the melting point can help you determine how long or how hot to burn the tested object while at the same time determining the safety requirements.

Explanation:

4 0
2 years ago
Read 2 more answers
Pls help i beg
marusya05 [52]

Answer:

The increasing order of conductivity is O< Ge< Mn.

Explanation:

Electrical conductivity is defined as the measure of the ability of a material to conduct electrical current through it. The conductivity depends on the atomic and molecular structure of the material.

Metals are good conductors because they have a structure with many electrons with weak bonds, and this allows their movement instead non-metals have between four and eight valence electrons, which lack this tendency.

The conductivity increases in the periodic table from top to bottom and from right to left.

oxygen is a nonmetal therefore it is a bad conductor.

Germanium is a metalloid whose conductivity is greater than a nonmetal and worst than a metal.

Manganese is a metal,in this case, it is a good conductor.

4 0
2 years ago
Which of the following is not part of the proper protocol for using acids and bases?
Anni [7]

Answer:

B.Add acid to water,not water to acid

Explanation:

they should not be mixed

8 0
3 years ago
Conner is testing the pH of a swimming pool and he finds it to be 6.5. The optimal pH for swimming is between 7.7 and 7.6. Conne
miv72 [106K]

Answer:

B.) He added a base to raise the PH

Explanation:

Took test

6 0
2 years ago
using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5
soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

5 0
3 years ago
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