Answer:
Q = 1964 J
Explanation:
Data Given:
latent heat of fusion for Lead (Lf)= 23.1 J/g
amount of ice (mass) = 85.0 gram
heat required to melt lead (Q) =?
Solution:
Latent heat of fusion: the amount of heat that required to melt certain amount of a substance. The total heat absorbed by substance is proportional to the total heat of fusion of the material.
Formula Used
Q = mLf
Q = heat required to melt a substance
m = mass of the substance
Lf =latent heat of fusion
put values in above formula
Q = mLf
Q = 85 g x 23.1 J/g
Q = 1964 J
Answer:
2.60 M
Explanation:
M1V1=M2V2
Where
M1 = ?
V1 = 20.9 mL
M2 = 2.548 M
V2 = 21.39 mL
(?)(20.9 mL) = (2.548 M)(21.39 mL)
------------------ -----------------------------
(20.9 mL) (20.9 mL)
? = (54.50)/(20.9) = 2.60 M
(Side Note: the mL cancel each other out to leave M units only)
Answer:
one mole of water contains 6.02 x 1023 MOLECULES of water.
But each molecule of water contains 2 H and 1 O atom = 3 atoms, so there are approximately 1.8 x 1024 atoms in a mole of water.
Explanation: