How to answer part d) ??

What is the relationship between DE and FG ? Select all that apply.

marysya [2.9K]

Could you add more information like the picture of the figure where these lines are from?

3 0

3 years ago

Read 2 more answers

Here are the steps Tyler took to solve the equation.

Finger [1]

Algebraic expressions include both alphabet and number so that the value of the alphabet is to be determined. Thus the steps taken by Tyler are correct if x = 22.

ii. Tyler made no mistake.

Algebraic expressions include both alphabet and number so that the value of the alphabet is to be determined. The value of the alphabet in the expression would be determined by applying mathematical operations appropriately.

To solve the question given to Tyler, we have:

$\sqrt{x + 3}$ = -5

square both sides of the equation to have;

(x + 3) = $(-5)^{2}$

x + 3 = 25

collect like terms to get;

x = 25 - 3

= 22

x = 22

1. Thus the equation is true if x = 22.

2. Tyler did not make any mistake in solving for x.

For more clarifications on algebraic expressions, visit: brainly.com/question/4344214

#SPJ 1

3 0

2 years ago

A phone manufacturer wants to compete in the touch screen phone market. Management understands that the leading product has a le

CaHeK987 [17]

Answer:

Step-by-step explanation:

Hello!

To compete in the touch screen phone market a manufacturer aims to release a new touch screen with a battery life said to last more than two hours longer than the leading product which is the desired feature in phones.

To test this claim two samples were taken:

Sample 1

X: battery lifespan of a unit of the new product (min)

n= 93 units of the new product

mean battery life X[bar]= 8:53hs= 533min

S= 84 min

Sample 2

X: battery lifespan of a unit of the leading product (min)

n= 102 units of the leading product

mean battery life X[bar]= 5:40 hs = 340min

S= 93 min

The population variances of both variances are unknown and distinct.

To test if the average battery life of the new product is greater than the average battery life of the leading product by 2 hs (or 120 min) the parameters of interest will be the two population means and we will test their difference, the hypotheses are:

H₀: μ₁ - μ₂ ≤ 120

H₁: μ₁ - μ₂ > 120

Considering that there is not enough information about the distribution of both variables, but both samples are big enough, we can apply the central limit theorem and approximate the distribution of both sample means to normal, this way we can use the standard normal:

$Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} } }$

Z≈N(0;1)

$Z= \frac{(533-340)-120}{\sqrt{\frac{84^2}{56} +\frac{93^2}{102} } }= 5.028$

I hope this helps!

3 0

4 years ago

Solve for m. 3m+7/2=−2m+5/2 A.-1 B.-1/5 C.6 D.6/5

dedylja [7]

To solve this we must isolate x which involves having the variables on one side and the numbers on the other.

First add 2m to both sides

3m+7/2=-2m+5/2

5m+7/2=5/2

Then we subtract 7/2 from both sides

5m+7/2=5/2

5m=-1

Finally we divide both sides by 5

5m/5=-1/5

Our final answer is -1/5

So the answer is B

Hope this helps!

6 0

3 years ago

4m-3n=8, for m wats yeah

stealth61 [152]

The answer would be (8+3n)/4

7 0

3 years ago