<u>Answer:</u>
Those cells that develop differently are referred to Specialised Cells.
<u>
</u><u>Explanation:</u>
Specialised cells are the one that is assigned to perform a specific role. Every specialised cell in the body is assigned to do their own job. The special features in them help them to perform their functions effectively.
Examples of specialised cells are- red blood cells (they are responsible to carry oxygen in the body), nerve cells (specialises in transmitting electrical signals) and muscle cells (brings body parts together).
Answer:
The new volume is 5.37 L
Explanation:
Step 1: Data given
Initial volume = 10.0 L
Initial temperature = 22.0 °C
Initial pressure = 1.00 atm
Final temperature = 202 °C
Final pressure = 3.00 atm
Step 2: Calculate final volume
(P1*V1)/T1 = (P2*V2)/T2
⇒ with P1 = The initial pressure = 1.00 atm
⇒ with V1 = The initial volume = 10.0 L
⇒ with T1 = The initial temperature = 22 °C = 295 Kelvin
⇒ with P2 = The final pressure = 3.00 atm
⇒ with V2 = The final volume = TO BE DETERMINED
⇒ with T2 = The final temperature = 202 °C = 475 Kelvin
(1.00 * 10.0) / 295 = (3.00 * V2) / 475
10 / 295 = 3V2/ 475
3V2 = 4750/295
V2 = 5.37 L
The new volume is 5.37 L
Answer:- 1.35 grams of NaF must be added.
Solution:- HF is a weak acid. So, if NaF is added to it then a buffer solution will be formed and the Handerson equation is used for buffer solutions to find out the pH. Since the pH is given, so we could easily calculate the moles and then grams of NaF required to achieve the mentioned pH.
Handerson equation is:
Moles of HF could be calculated from it's given volume and molarity as:
= 0.025 mol HF
pKa is calculated from given Ka value using the formula:
pKa = 3.14
Let's plug in the values in the Handerson equation:
On taking antilog:
base = 0.03225 mol
Molar mass of NaF is 41.99 grams per mol. Let's multiply the moles by molar mass to get the grams of NaF.
= 1.35 g
So, 1.35 grams of NaF must be added to 50.0 mL of 0.500 M HF solution to achieve a pH of 3.25.
<span>Given: energy released = 17.59 MeV per deuterium/tritium reaction pair (mass = 5 amu)
List the balanced nuclear reaction.
</span>
²₁H + ³₁H → ⁴₂He + ¹₀n
Hope this helps
Answer:
Denitrification changes nitrogen into a gaseous form.
Explanation: