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3 years ago

There are diffrent types of cells for every job in your body. How do we refer to those cells that develop differently?

Chemistry

1 answer:

kotykmax [81]3 years ago

3 0

Answer:

Those cells that develop differently are referred to Specialised Cells.

Explanation:

Specialised cells are the one that is assigned to perform a specific role. Every specialised cell in the body is assigned to do their own job. The special features in them help them to perform their functions effectively.

Examples of specialised cells are- red blood cells (they are responsible to carry oxygen in the body), nerve cells (specialises in transmitting electrical signals) and muscle cells (brings body parts together).

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it is a i believe: Bicarbonate and carbonic acid (A)

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What is the charge of the following polyatomic ions

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Answer:

Explanation:

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3 years ago

How many grams of water are produced when oxygen reacts with an excessive amount of propane (C3H8)?

lora16 [44]

Answer:

From the equation you will see that 1 mol of propane generates 4 mols of water.

Since the molar mass of water

M ( H2O)=2×1+16=18g/mol

2 mol propane will generate

2 ×4×18=144g of water

Explanation:

Since the molar mass of water

M ( H2O)=2×1+16=18g/mol

2 mol propane will generate

2 ×4×18=144g of water

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3 years ago

Cuanto pesan 2 moles de HCI

maks197457 [2]

Answer:

FORMULA: HCl PESO MOLECULAR: 36.46 g/mol COMPOSICION: Cl: 97.23 % y H: 2.76 %. GENERALIDADES: El ácido clorhídrico es una disolución acuosa de cloruro de hidrógeno.

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3 years ago

Serial dilution problem: Six test tubes are placed in a rack. To each tube add 4 mL of saline solution. Now to the first tube ad

ArbitrLikvidat [17]

Answer:

The dilution factor of protein in tube # 4 is 125. Molar concentration is 0.0088 M protein

Explanation:

The dilution factor indicates how many times is more concentrated a main solution in relationship with a diluted solution. In this case, the main solution is in tube #1. For calculating the dilution factor and molar concentration in tube #4 we need the main solution concentration which comes from next equation:

Initial volume * initial concentration = final volume * final concentration

0.5 mL * 10M = 5mL * final concentration

1.1 M = final concentration = main solution concentration

Applying the same equation for remain tubes we have 0.22 M for tube #2, 0.044 M for tube # 4 and 0.0088 for tube # 4.

Dilution factor = Main solution concentration/tube 4 concentration

Dilution factor = 1.1/0.0088 = 125

I hope my answer helps you

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3 years ago