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Nataly [62]
3 years ago
11

There are diffrent types of cells for every job in your body. How do we refer to those cells that develop differently?

Chemistry
1 answer:
kotykmax [81]3 years ago
3 0

<u>Answer:</u>

Those cells that develop differently are referred  to Specialised Cells.

<u> </u><u>Explanation:</u>

Specialised cells are the one that is assigned to perform a specific role. Every specialised cell in the body is assigned to do their own job. The special features in them help them to perform their functions effectively.

Examples of specialised cells are- red blood cells (they are responsible to carry oxygen in the body), nerve cells (specialises in transmitting electrical signals) and muscle cells (brings body parts together).  

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Answer:

B.

Explanation:

One mole is the amount of substance that contain the Avogadro number which is equal to 6.022×10^23 atom, molecules or ions.

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What is scientific explanation of the structure of atoms and how they interact with other atoms? (F) be element (g)compound (k)a
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What is the ph of a 0.25 m solution of c6h5nh2 given that its kb is 1.8 x 10-6?
IrinaK [193]

The pH a 0.25 m solution of C₆H₅NH₂ is equal to 3.13.

<h3>How do we calculate pH of weak base?</h3>

pH of the weak base will be calculate by using the Henderson Hasselbalch equation as:

pH = pKb + log([HB⁺]/[B])

pKb = -log(1.8×10⁻⁶) = 5.7

Chemical reaction for C₆H₅NH₂ is:

                          C₆H₅NH₂ + H₂O → C₆H₅NH₃⁺ + OH⁻

Initial:                     0.25                           0            0

Change:                    -x                             x             x

Equilibrium:        0.25-x                           x             x

Base dissociation constant will be calculated as:
Kb = [C₆H₅NH₃⁺][OH⁻] / [C₆H₅NH₂]

Kb = x² / 0.25 - x

x is very small as compared to 0.25, so we neglect x from that term and by putting value of Kb, then the equation becomes:

1.8×10⁻⁶ = x² / 0.25

x² = (1.8×10⁻⁶)(0.25)

x = 0.67×10⁻³ M = [C₆H₅NH₃⁺]

On putting all these values on the above equation of pH, we get

pH = 5.7 + log(0.67×10⁻³/0.25)

pH = 3.13

Hence pH of the solution is 3.13.

To know more about Henderson Hasselbalch equation, visit the below link:
brainly.com/question/13651361

#SPJ4

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Tar pits.

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