This indicates that the reaction is exothermic meaning that it releases heat/energy
Answer:
0.0457M is molarity of nitrate anion in the solution.
Explanation:
Molarity is defined as the ratio between moles of solute (In this case, nitrate ion) and liters of solution (The total volume of the solution is 300.0mL = 0.300L).
Thus, we need to convert mass of Lead(II) nitrate to moles using its molar mass (Molar mass Pb(NO₃)₂: 331.2 g/mol). Moles of Pb(NO₃)₂ = 1/2 Moles of NO₃⁻:
<em>Moles Pb(NO₃)₂ and moles of NO₃⁻:</em>
2.27g * (1mol / 331.2g) = 0.006854 moles Pb(NO₃)₂ * (2moles NO₃⁻ / 1mol Pb(NO₃)₂) = 0.0137moles NO₃⁻
Molarity is:
0.0137 moles NO₃⁻ / 0.300L =
<h3>0.0457M is molarity of nitrate anion in the solution </h3>
KIO4 is an example of polyatomic ion.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion.
The charge on this polyatomic ion is 0.
To get the oxidation number of I, we will let x as the oxidation number of I.
We can get the oxidation number of Iodine by solving like this;
KIO4 : (+1) + x + 4(-2) = 0
(+1) + x - 8 = 0
x - 7 = 0
x = +7
Therefore, the oxidation number of iodine atom in KIO4 is +7.
Your answer is J, because electrons orbit the nucleus of an atom and have a negative charge