All categories

2 years ago

Which of these is an example of something a civil engineer would deal with?

Chemistry

1 answer:

kiruha [24]2 years ago

8 0

Answer:

Earthquake engineering

Aerospace engineering

Coastal engineering

Hydraulic engineering

environmental engineering

construction engineering

structural engineering

You might be interested in

What is the balanced chemical equation for potassium and chlorine which form potassium chloride

ArbitrLikvidat [17]

Potassium metal + Chlorine Gas --------> Potassium Chloride
The chemical equation using symbols and formula is
K (s) + Cl2 (g) ---------> 2KCl (s)

3 0

3 years ago

Read 2 more answers

Calculate the density of an object with a mass of 220 and a volume of 145mL.

LiRa [457]

Answer:

1.52 g/mL

Explanation:

The formula for finding the density of an object is d = m/v, or density = mass divided by volume.

Therefore, we can input the two values and solve for d.

d = 220/145

d = 44/29

d ≈ 1.52 g/mL

8 0

3 years ago

A relatively simple way of estimating profit is to consider the the difference between the cost (the total spent on materials an

Maksim231197 [3]

Answer: it shows that 1mol mCPHA provides the oxygens to 1 mol of propene, to make 1 mole of C3H6O so: 1 mol C3H6 & 1 mol mCPHA --> 1 mol C3H6O using molar masses, that equation becomes: 42.08grams C3H6 & 172.57grams mCPHA --> 58.08grams C3H6O which is: 42.08 kg C3H6 & 172.57 kg mCPHA --> 58.08 kg C3H6O to produce 1 kg of C3H6O, this becomes: 42.08 / 58.08 kg C3H6 & 172.57 / 58.08 kg mCPHA --> 58.08 /58.08 kg C3H6O which is: 0.72452 kg C3H6 & 2.9712 kg mCPHA --> 1 kg C3H6O but because the reaction gives only a 96% yield, we scale up the reactants to get that desired 1 kg of C3H6O (0.72452 kg ) (100/96) C3H6 & (2.9712 kg) (100/96) mCPHA --> 1 kg C3H6O which is: 0.75471 kg C3H6 & 3.095 kg mCPHA --> 1 kg C3H6O ========= costs per kg of C3H6O produced: (0.75471 kg C3H6) ($10.97 per kg) = $8.279 (3.095 kg mCPHA) ($5.28 per kg) = $16.342 & (0.75471 kg C3H6) / (0.0210 kg C3H6 / L dichloromethane) = 35.939 Litres dichloromethane (35.939 Litres dichloromethane) ($2.12 per L) = $ 76.19 & waste disposal is $5.00 per kilogram of propene oxide produced total cost, disregarding labor,energy, & facility costs: $8.279 & $16.342 & $ $ 76.19 & $5.00 = $105.81 per kg C3H6O produced ========== profit: ($258.25 / kg C3H6O) - ($105.81 cost per kg) = $152.44 profit /kg â€śCalculate the profit from producing 75.00kg of propene oxideâ€ť (75.00kg) ($152.44 /kg) = $11,433 that answer rounded off to four sig figs, is $11,430

7 0

3 years ago

Hbr(aq)+h2o(l)→h3o+(aq)+br−(aq) express your answers as a chemical expressions. enter your answers in order given in the questio

tamaranim1 [39]

This is an incomplete question, here is a complete question.

For each reaction, identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid, and the conjugate base.

$HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)$

Express your answers as a chemical expressions. Enter your answers in order given in the question separated by commas.

Answer : The given equilibrium reaction will be,

$HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)$

Acid Base Conjugate Conjugate

acid base

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

The given equilibrium reaction will be,

$HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)$

Acid Base Conjugate Conjugate

acid base

In this reaction, $HBr$ is an acid that donate a proton or hydrogen to $H_2O$ base and it forms $Br^-$ and $H_3O^+$ are conjugate base and acid respectively.

8 0

3 years ago

Why is a standard system of measurement important?

GrogVix [38]

I believe the correct response is A.

8 0

3 years ago

Read 2 more answers