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r-ruslan [8.4K]
3 years ago
9

NEED HELP ASAP!!!

Physics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

The answer is A)

Explanation:

The wall pushes back on you with the same force.

This is easily analyzed since when pushing or applying force toward the wall it does not move, it can be said that the system is in balance, this mathematically corresponds to that the sum of forces will be equal to zero, for this to be true the wall must apply an equal force and opposite to the force applied on the wall.

The above corresponds to newton's third law which says: Newton's Third Law also known as the principle of action and reaction tells us that if a body A exerts an action on another body B, it performs on another action-equal and of opposite sense.

An example of this can be seen in the attached image.

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PLS HELP WILL MARK BRAINLIEST IF RIGHT NEED IMMEDIATELY PLEASEEEEE
timofeeve [1]

Answer:

Explanation:

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3 0
3 years ago
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For a converging lens, a ray arriving parallel to the optic axis
mixer [17]

Answer:

b. passes through the principal focal point.

Explanation:

Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.

Basically, there are two (2) main types of lens and these includes;

I. Diverging (concave) lens.

II. Converging (convex) lens.

A converging lens refers to a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image. This type of lens is usually thin at the lower and upper edges and thick across the middle.

For a converging lens, a ray arriving parallel to the optic axis passes through the principal focal point.

8 0
3 years ago
Which nutrient is the most difficult to break down and, thus, is generally used last for energy in the body?
photoshop1234 [79]

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proteins

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3 years ago
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Three charges are on a line. A positive charge is on the far left labeled q Subscript 1 baseline positive 6 Coulombs. The second
tiny-mole [99]

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4 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
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