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r-ruslan [8.4K]
3 years ago
9

NEED HELP ASAP!!!

Physics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

The answer is A)

Explanation:

The wall pushes back on you with the same force.

This is easily analyzed since when pushing or applying force toward the wall it does not move, it can be said that the system is in balance, this mathematically corresponds to that the sum of forces will be equal to zero, for this to be true the wall must apply an equal force and opposite to the force applied on the wall.

The above corresponds to newton's third law which says: Newton's Third Law also known as the principle of action and reaction tells us that if a body A exerts an action on another body B, it performs on another action-equal and of opposite sense.

An example of this can be seen in the attached image.

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Which of the following describes the variable that responds to a change?
timama [110]
Dependent variable is your answer.
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3 years ago
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Un contenedor de 1800 N está en reposo sobre un plano inclinado a 28°, el coeficiente de fricción entre el contenedor y el plano
babunello [35]

Answer:

F = 1480.77N

Explanation:

In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:

F-Wsin\alpha-F_r=0\\\\F-Wsin\alpha-N\mu cos\alpha=0\\\\F-Wsin\alpha-W\mu cos\alpha=0     (1)

F: required force = ?

W: weight of the container = 1800N

N: normal force = weigth

α: angle of the incline = 28°

g: gravitational acceleration = 9.8m/s^2

μ: coefficient of friction = 0.4

You solve the equation (1) for F and replace the values of the other parameters:

F=W(sin\alpha+\mu cos\alpha)\\\\F=(1800N)(sin28\°+(0.4)cos28\°)=1480.77N

The required force to push the container for the incline with a constant velocity is 1480.77N

8 0
3 years ago
Four forces are exerted on each of the two objects shown below:
exis [7]

Answer: Object A but not Object B.

Explanation:

6 0
3 years ago
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compare 51.5 hectograms to 51500 decigrams. How do each of these values compare to a gram, and which represents a larger mass?
Olin [163]
These values when compared seem to be the same. They are equal. If we convert them to the same units, they results to the value which is:
 
51.5 Hectograms = 5100 Grams

51,500 Decigrams = 5100 Grams


Hope this answers the question. Have  a nice day.

7 0
3 years ago
Electrons of wavelength 1.5 nm are emitted from a material when light of wavelength 350nm is incident on it. What is the work fu
krok68 [10]

Answer:

3.5434 eV

Explanation:

For a particle with kinetic energy E and mass m , the wavelength  associated is given by the following relation,

\lambda=\frac{h}{\sqrt{2mE} }

E = \frac{h^2}{2m\lambda^2}

Putting the values  we get

E = \frac{(6.6\times(10^{-34})^2}{2\times9.1\times10^{-31\times(1.5\times10^{-9})^2}}

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= .0066 eV.

Energy of¹light in terms of eV

= 1244 / 350 = 3.55 eV.

Work function = 3.55 - 0.0066 = 3.5434 eV.

7 0
4 years ago
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