The correct answer of this question is : Negative focal length and virtual images.
EXPLANATION:
The concave lens is that transparent spherically refracting surface which is diverging in nature. It is so because it is bulged at the edges and thinner in the centre.
The focal length of the concave lens is always taken negative.
As the lens is diverging in nature, it always forms virtual,erect and diminished image. It means the image formed by concave lens has less size as compared to object.
Hence, the correct answer of this question is that concave lenses have negative focal length and always form virtual images.
Answer:
it must move back and forth during sex
We know, momentum = mass * speed
25kgm/s = 2 kg * s
s = 25/2 = 12.5 m/s
Answer:
Vf = 4.40 m/s and θ = 88º
Explanation:
To solve this problem, let's look for the resultants of the force and with this we calculate the accelerations in each axis.
Let's use trigonometry to break down the forces
Sin 25 = F1x / F1
Cos 25 = F1y / F1
Fix = F1 sin 25
F1x = 1.85 sin 25
F1x = 0.78 N
F1y = 1.85 cos 25
F1y = 1.67 N
F2 = - 0.782 N j ^ (south)
F3 = - 0.750 N i ^ (west)
We write Newton's second law
X axis (East-West)
F1x - F3 = m ax
ax = (F1x - F3) / m
ax = (0.78 - (0.750)) / 0.325
ax = 0.092 m / s²
Y axis (North-South)
F1y - F2 = m ay
ay = (1.67- (0.782)) / 0.325
ay = 2.73 m / s²
Let's calculate the magnitude and direction of the acceleration
a = RA ax2 + ay2
a = RA 0.092² + 2.73²
a = 2.73m / s²
tan θ = ay / ax
θ = tan⁻¹ (2.73/0.092)
θ = tan⁻¹ 29.67
θ = 88º
We calculate the speed, notice that we use the total acceleration to be able to use the totol displacement
Vf² = vo² + 2 at D
Vf² = 0 + 2 2.73 3.55
Vf = √ 19.38
Vf = 4.40 m / s
θ = 88º
A. They must have a potential difference
Potential difference is voltage and voltage is basically the thing that causes current to flow
