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2 years ago

3

a volleyball reaches its maximum height of 13 feet 3 seconds after its served which of the following quadratics could model the

height of the volleyball over time after its served, select all that apply

2 answers:

ivolga24 [154]2 years ago

0 0

The answer is f(X)= -2x^2 + 12x - 5, or the answer is best represented by the second option.

Because if you do, -b/2a, the result you'd get is three which represents the time of the ball after it's served.

Plug that number into the quadratic equation, and you should be getting thirteen as the result.

Lunna [17]2 years ago

0 0

Answer:

the answers are the second option and the fifth option, i took the alegbra nation and those were marked correct

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Using the relationships between

Pavlova-9 [17]

Answer:

They will always intersect at one point

Step-by-step explanation:

^^

6 0

1 year ago

Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

7 0

3 years ago

Hi ! How to solve this question?

tester [92]

You should actually have

$-x^2-4x-10=-(x^2+4x+10)=-(x^2+4x+4+6)=-((x+2)^2+6)=-(x+2)^2-6$

Now, remember that $x^2$ is always non-negative, so $(x+2)^2\ge0$ for any value of $x$ . This means $-(x+2)^2\le0$ for any $x$ , and so

$-(x+2)^2-6\le0-6=-6$

i.e. f(x) is at most -6, and hence negative for all $x$ .

4 0

2 years ago

Jan has $28 to spend at the carnival.

a_sh-v [17]

Answer:

5 rides.

Step-by-step explanation:

$28 - $6.50 = $21.50

$21.50 - $4 = $17.5

$17.5 ÷ $3 = 5.83

7 0

2 years ago

Read 2 more answers

A baby outfit uses 2/9 square yard of fabric for the hat and 5/9 square yards of fabric for the bib. A tailor has 5 4/9 square y

Ludmilka [50]

Answer:

She can make<u> 7 </u>baby outfits.

Step-by-step explanation:

Given:

A baby outfit uses 2/9 square yard of fabric for the hat and 5/9 square yards of fabric for the bib.

A tailor has 5 4/9 square yards of fabric.

Now, to find the outfits she can make.

So, we add to get the total fabric used for baby outfits hat and bib:

$\frac{2}{9} +\frac{5}{9}\ square\ yards.$

$=\frac{2+5}{9}\ square\ yards.$

$=\frac{7}{9}\ square\ yards.$

Total fabric used for outfit = $=\frac{7}{9}\ square\ yards.$

Total fabric tailor has = $5\frac{4}{9} =\frac{49}{9}\ square\ yards$

Now, to get the number of outfits from the fabric tailor has we divide by total fabric used for outfit:

Number of outfits = Total fabric tailor has ÷ Total fabric used for outfit.

$Number\ of\ outfits = \frac{49}{9} \div\frac{7}{9}$

<em>Thus, on dividing we get:</em>

$Number\ of\ outfits = 7\ outfits.$

Therefore, she can make 7 baby outfits.

6 0

3 years ago