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yaroslaw [1]
3 years ago
10

Emmerson rented an apartment for $10,245.75 for the first year she lived in the

Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer:It’s 63427.90

Step-by-step explanation:

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What is the measure of Zc<br>​
maks197457 [2]

Answer: 56 degrees

Step-by-step explanation:

We know that angle between b and c is 90 degrees. Because there is a line dividing angles a and b from 124 and c, we also know that each side is 180 degrees (a and b add to 180, and 124 and c add to 180).

124 and c are supplementary angles. We can represent this in an equation to solve for c:

124 + c = 180\\\\c = 56

3 0
3 years ago
When y=7.5 x=2 what is the value of y when x is 2 1/4
swat32
<h2>Answer:</h2>

The value of y is 8.4375

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • y = 7.5
  • x = 2

<h3>Asked :</h3>
  • The value of y when x is 2.25

<h3>Solution :</h3>

2/7.5 = 2.25/y

Do a cross multiplication,

2/7.5 = 2.25/y

=> 20/75 = 2.25/y

=> 75 . 2.25 = 20y

=> 168.75 = 20y

Reverse the equation,

168.75 = 20y

=> 20y = 168.75

Find the value of y,

20y = 168.75

=> y = 8.4375

<h3>Conclusion :</h3>

y = 8.4375

7 0
3 years ago
Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2
boyakko [2]

<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

6 0
3 years ago
Read 2 more answers
If one factor is (x+1), what is the other factor?
Brrunno [24]
If you need anything else just tell me but I need more info for the
Answer
5 0
3 years ago
What values of a, b, and c would you use in the quadratic formula for the following equation? 6x^2+5x-4=0
Yanka [14]
So remember that in a quadratic equation there is a type of quadratic equation of the form ax^2+bx+c=0 so to find what values of a, b, and c you need for the quadratic formula, you need to look at your equation and label a, b, and c. In this equation a=6, b=5 and c=-4. So for the quadratic formula you would use a=6, b=5 and C=-4. I hope this helps!!!!!

5 0
3 years ago
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