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yaroslaw [1]
3 years ago
10

Emmerson rented an apartment for $10,245.75 for the first year she lived in the

Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer:It’s 63427.90

Step-by-step explanation:

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Tampa Bay Buccaneers Super Bowl Contenders?
mafiozo [28]

Answer:

Australia.

Bangladesh.

England.

India.

New Zealand.

South Africa.

Sri Lanka.

West Indies.

Step-by-step explanation:

none

hope this helps

6 0
3 years ago
In ΔGHI, i = 75 cm, h = 12 cm and ∠H=22°. Find all possible values of ∠I, to the nearest 10th of a degree.
SOVA2 [1]

Answer:

No Possible Triangles

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Jeff earns $27,800 per year, what is his bi-monthly gross pay?
harina [27]
So you would take the monthly pay which is 2,316.666(repeating) then you would multiply that by two for the bi-monthly gross pay. which leaves you with the answer of 

4,633.333(repeating)
8 0
3 years ago
Question 1 of 4
matrenka [14]

Answer:

1) What is the average score of the student surveyed?

b. 52.5

2) What is the median of the student's surveyed?

52.5

3) How many students were surveyed?

20 students

Step-by-step explanation:

1) What is the average score of the student surveyed?

Average score of the student's been surveyed means we should calculate the mean of the above scores

The formula for Mean = Sum of the number of terms/ Number of terms

Number of terms = 20

Average(Mean score) =

25 + 30 + 35 + 40 + 40 + 45 + 45 + 50 + 50 + 50 + 55 + 55 + 55 + 60 + 60 + 65 + 65 + 70 + 75 + 80/20

= 1050/20

= 52.5

2) What is the median of the student's surveyed?

25, 30, 35, 40, 40, 45, 45, 50, 50, 50, 55, 55, 55, 60, 60, 65, 65, 70, 75, 80

From the above data, we can see that 20 students were surveyed. To find the Median, we find the sum of the 10th value and the 11th value and we divide by 2

Hence,

25, 30, 35, 40, 40, 45, 45, 50, 50,) 50, 55, (55, 55, 60, 60, 65, 65, 70, 75, 80

10th value = 50

11th value = 55

Median = 50 + 55/2

= 105/2

= 52.5

3) How many students were surveyed?

Counting the results of the survey, the number of students that were surveyed = 20 students

3 0
3 years ago
A clinical psychologist wants to test whether experiencing childhood trauma affects one's self-efficacy in adulthood. He randoml
Verdich [7]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 152.5

For the alternative hypothesis,

µ ≠ 152.5

This is a two tailed test.

Since no population standard deviation is given, the distribution is a student's t.

Since n = 231

Degrees of freedom, df = n - 1 = 231 - 1 = 230

t = (x - µ)/(s/√n)

Where

x = sample mean = 148.9

µ = population mean = 152.5

s = samples standard deviation = 27.4

t = (148.9 - 152.5)/(27.4/√231) = - 2

We would determine the p value using the t test calculator. It becomes

p = 0.047

Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals

6 0
3 years ago
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