A. - (lambda) per unit length of the inner surface of the cylinder<span>b. (lambda)outer = 3 (lambda)
</span><span>c. E= 3(lambda)/(4 pi epsilon(0) r^2)</span>
Beginning when the bottom of the object first touches the water,
and as it descends and more and more of it goes under, the
buoyant force on it increases during that time.
As soon as the object is completely underwater, it doesn't matter
how deep under it is, the buoyant force on it remains the same.
Answer:
13.8 N
Explanation:
Pressure on the one end of the hydraulic system = Pressure on the other end
Pressure = Force / Area where Force is in Newton, area is in m²
so Force of one end (F1) / area of that end = force of the other end (F2) / area of that end
3112 / ( 707 /10000) in m² = F2 / ( 3.14 / 10000) in m²
cross multiply
44016.97 × 0.000314 = 13.82 N
Answer:
b) 0.5 m/s
Explanation:
let V be the averare speed of the object.
the average speed is given by:
V = total distance / total time
= (20+20)/(30+50)
= 0.5 m/s
Therefore, the average speed of the object is 0.5 m/s.
#include<studio.h>
int main( )
{
int n;
int a,b,c,d,x,y;
int avarage;
printf("enter value of n:\n");
scanf("%d",&n);
printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);
scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);
sum=(a+b+c+d+x+y);
avarage=(sum/n);
print f("%d",avarage);
if
{
n=positive interger
}
else
{
printf ("n must be positive");
}
return 0;
}
