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photoshop1234 [79]
3 years ago
7

Weight and mass are interchangeable terms. True or False

Physics
2 answers:
Fynjy0 [20]3 years ago
8 0
False
weight (N-force) = mass(kg-matter) x g

strictly in Physics, both are not interchangeable.
in normal life, weight (kg) actally means mass in Physics.
Nonamiya [84]3 years ago
5 0
It's false. Mass is a way of measuring how much matter an object contains, where as weight measures how hard gravity is pulling on an object. While on earth, these are typically interchangeable. However, if you were to go to Mars, your mass would stay the same, but the weight will be different. This is because you still contain the same amount of matter, but the gravity's pull will be different because the moon has a different gravitational pull than the earth. Hope this helps!
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<span>b. They share their experimental results with other researchers</span>
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Find the acceleration for a force of 2 N acting on 2 kg.
igomit [66]

Answer:

The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.

4 0
3 years ago
Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N
Simora [160]

The coefficient of friction is 0.363

Explanation:

There are two forces acting on the scooter in the horizontal direction:

- The applied force, F = 1850 N, forward

- The frictional force, F_f, backward

Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:

F-F_f = 0\\F_f = F = 1850 N

The frictional force can be written as

F_f = \mu R (1)

where

\mu is the coefficient of friction

R is the normal reaction of the ground on the scooter

For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:

R = W = mg

where

m = 520 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

Substituting into (1),

F_f = \mu mg = 1850 N

and solving for \mu,

\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

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brainly.com/question/2235246

#LearnwithBrainly

5 0
3 years ago
The 25-mph zone is 150 yards long. How much time did the student save (in seconds) by speeding past the school
VikaD [51]

Answer:

Time = 12.27seconds

Explanation:

Given

Speed = 25miles/hour

Distance = 150 yards = 150(0.000568182)miles

Distance (in miles) = 0.0852273miles

Get the time

Speed = Distance/Time

Time = Distance/Speed

Time = 0.0852273/25

Time = 0.0034hours

Time = 0.0034 * 3600secs

Time = 12.27seconds

7 0
3 years ago
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