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Evgen [1.6K]
3 years ago
13

Which statement describes all chemical changes but not all physical changes.

Physics
2 answers:
Akimi4 [234]3 years ago
7 0

Answer:

what are the statements so i can help just comment and i will get back to you

Explanation:

ki77a [65]3 years ago
3 0

Answer:

burning, cooking, rusting, and rotting.

Explanation:

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7. How much work is done in moving a charge of 10 micro coulombs 1 meter along an equipotential of 10 volts?
Neko [114]

It takes work to push charge through a change of potential. 
There's no change of potential along an equipotential path,
so that path doesn't require any work.

8 0
3 years ago
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Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of
natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

r'=4.12\ m

We need to calculate the path difference

Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

\lambda=1.143\ m

We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

7 0
3 years ago
Pleae answer asap brcianset
marshall27 [118]

Answer:

>

Explanation:

1/8 is greater than 3/20

5 0
3 years ago
How much time does it take a person to walk 12km north at the velocity at a velocity of 6.5 km/hrs?
alukav5142 [94]

"6.5 km/hr" is not a velocity.  It's just a speed, so
we don't know what direction he's walking.

If he happens to be walking north, then it takes him

               (12 km) / (6.5 km/hr)  =  1.846... hours  (rounded) .

If he's walking in any other direction, it takes him longer than that.

If the angle between north and the direction he's walking is
90 degrees or more, then he can never cover any northward
distance, no matter how long he walks.

6 0
3 years ago
Read 2 more answers
Just this last one!!
Pepsi [2]

Answer:

47 \ \frac{m}{s}

Explanation:

s = displacement (m)

u = initial velocity (\frac{m}{s})

v = final velocity (\frac{m}{s})

a = acceleration (\frac{m}{s^{2} })

t = time (s)

s = 235

a = -4.7

v = 0

v² = u² + 2as

(0)² = u² + 2(-4.7)(235)

u² - 2209 = 0

u² = 2209

u = 47

4 0
2 years ago
Read 2 more answers
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