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balandron [24]
2 years ago
7

How should 13,079 be written in in expanded form​

Mathematics
2 answers:
Triss [41]2 years ago
8 0

Answer:

10000.  3000. 70.  9

Step-by-step explanation:

Thepotemich [5.8K]2 years ago
5 0

Answer:

10,000 + 3,000 + 70 + 9

Step-by-step explanation:

It will be 10,000 + 3,000 + 70 + 9

That is how expanded form works.

Hope it helps :)

If you have any questions ask me.

You might be interested in
How can you subtract mixed numbers when the fraction in the front number is less than the second fraction?
irakobra [83]
U have to find a common denominator
5 0
3 years ago
daren has 10 sweets .hellen has 30 sweets.faith has 4 fewer sweets than the average number of sweets daren,hellenand faith have.
Sunny_sXe [5.5K]

Answer:

16

Step-by-step explanation:

Average = the sum of all numbers divided by the amount of items in the set, so:

10+30=40

40/2=20

20-4=16

Hopefully this helps :) Good luck!

8 0
3 years ago
the temperature outside was 50 during the day and fell 16 at night. What was the temperature at night?
mamaluj [8]
You subtract 16 from 50

so 50-16=34

so your answer is 34 degree

7 0
3 years ago
Read 2 more answers
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
Need help not sure what to do
Rama09 [41]

5a)

2x + 94 = 7x + 49 (vertical angles are equal)

2x - 7x = -94 + 49

-5x = -45

x = 9

Answer

9

5b)

4y + 7x + 49 = 180 (supplementary angles, sum = 180)

4y + 7(9) + 49 = 180

4y + 112 = 180

4y = 68

y = 17

Answer

17

6)

x = 6x - 290 (vertical angles are equal)

-5x = -290

  x = 58

Answer

58


7 0
3 years ago
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