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salantis [7]
3 years ago
9

Solve 3log2^x=27. the ans for this is 8 please help me slove this

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
So we have the equation 3log2^{x}=27, and we want to solve for x.

First, we are going to apply the log of a power rule: loga^{x}=xloga
3log2^{x}=27
3xlog2=27

Next, we are going to divide both sides of the equation by 3log2:
3xlog2=27
\frac{3xlog2}{3log2} = \frac{27}{3log2}
x= \frac{27}{3log2}

Last but not least, we can use a calculator to evaluate the right hand side of the equation:
x= \frac{27}{3log2}
x=29.8974

We can conclude that the solution of our logarithmic function is x=29.8974. I don't know who told you that the correct answer is 8, but they is wrong.
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