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Crank
3 years ago
12

Two particles with positive charges q1 and q2 are separated by a distance s. Along the line connecting the two charges, at what

distance from the charge q1 is the total electric field from the two charges zero
Physics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

The distance is  z = \frac{1 +     \sqrt{ \frac{k *  q_2 }{   k *  q_1}}}{s}

Explanation:

From the question we are told that

   The positive charges is  q_1  \  and \  q_2

   The distance of separation is  s

   

Generally at the point where the electric field is zero  would be a point where

The  electric field due to q_1 =  The  electric field due to q_2

Generally the electric field due to q_1 is mathematically represented as

     E_1 =  \frac{k *  q_1}{ z^2 }

Since we are taking our reference from q_1 then the electric field due to q_2 is mathematically represented as

     E_2 =  \frac{k *  q_2}{ (s- z)^2 }

So

     \frac{k *  q_1}{ z^2 } =  \frac{k *  q_2}{ (s- z)^2 }

      k *  q_1 *   (s- z)^2=  k *  q_2 *  z^2

      [ \frac{s -z }{z} ]^2 =      \frac{k *  q_2 }{   k *  q_1}

      \frac{s -z }{z}  =     \sqrt{ \frac{k *  q_2 }{   k *  q_1}}

     \frac{s}{z}  - 1  =     \sqrt{ \frac{k *  q_2 }{   k *  q_1}}

     z = \frac{1 +     \sqrt{ \frac{k *  q_2 }{   k *  q_1}}}{s}

     

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