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pickupchik [31]
3 years ago
6

What is trapezord mean

Physics
1 answer:
igor_vitrenko [27]3 years ago
5 0
A quadrilateral with only one pair of parallel sides.
<span>a small carpal bone in the base of the hand, articulating with the metacarpal of the index finger.
</span>
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A box weighing 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied on t
Bogdan [553]

Answer:

the friction force in the reverse direction is 200 *0.4=80 N.

the net forward force acting on the box is therefore

Fnet= 100 - 80  N

= 20 N

acceleration = Fnet / mass

=Fnet *g/(weight)

=20 *9.8/200 = 0.98 m/s^2

Explanation:

4 0
3 years ago
Read 2 more answers
5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ
TiliK225 [7]

Answer:

v= 1.71 m/s

Explanation:

Given that

Distance between two successive crests = 4.0 m

 λ = 4 m

T= 7 sec

T is the time between 3 waves.

3 waves = 7 sec

1 wave = 7 /3 sec

So t= 7/3 s

We know that frequency f

f= 1/t= 3/7 Hz

Lets take speed of the wave is v

v= f λ

f=frequency

λ=wavelength

v= 3/7 x 4 = 12 /7

v= 1.71 m/s

3 0
3 years ago
A drag racer starts from the rest and accelerates at 7.4m/s^2.how far will he travel in 2.0 seconds?
Vesna [10]

Answer:

14.8 m

Explanation:

S= ut + \frac{1}{2}at^{2}

where u = initial velocity

S= (0 \frac{m}{s})(2s) + \frac{1}{2}(7.4\frac{m}{s^{2} })(2s^{2})

S=  \frac{1}{2}(7.4\frac{m}{s^{2} })(2s^{2})

S=14.8 m

8 0
3 years ago
A 250 g object is hung onto a spring. It stretches 18 cm. Find the spring's spring constant
Juliette [100K]
<h2>Answer: 13.61 N/m</h2>

Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force F applied to it, <u>as long as the spring is not permanently deformed</u>:

F=k (x-x_{o})    (1)

Where:

k is the elastic constant of the spring. The higher its value, the more work it will cost to stretch the spring.

x_{o} is the length of the spring without applying force.

x is the length of the spring with the force applied.

According to this, we have a spring where only the force due gravity is applied.

In other words, the force applied is the weigth W of the block:

W=m.g   (2)

Where m=250g=0.25kg is the mass of the block and g=9.8\frac{m}{s^{2}}  is the gravity acceleration.

W=(0.25kg)(9.8\frac{m}{s^{2}})   (3)

W=2.45N   (4)

Knowing the force applied W and x=18cm=0.18m and x_{o}=0, we can substitute the values in equation (1) and find k:

W=k (x-x_{o})    (5)

2.45N=k (0.18m-0m)    (6)

<u>Finally:</u>

k=13.61\frac{N}{m}  

4 0
3 years ago
se the model for projectile motion, assuming there is no air resistance and g = 32 feet per second per second. A baseball, hit 3
guajiro [1.7K]

Answer:

b

Explanation:

just took the test

8 0
3 years ago
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