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kompoz [17]
3 years ago
8

A small hot-air balloon is filled with 1.01×106 l of air (d = 1.20 g/l). as the air in the balloon is heated, it expands to 1.10

×106 l. what is the density of the heated air in the balloon?
Physics
1 answer:
lara31 [8.8K]3 years ago
5 0
<span>Volume of air in the balloon 1.01 x 10^6 L
 Density of air is 1.20 g/l
 Mass = Density X Volume

 So mass of the air in the Balloon= ( 1.01 x 10^6) X 1.20 = 1.212 x 10^6 g
 As the air is heated, the volume of air in the balloon expands to 1.10x 10^6 L Density= Mass/ voume So the Density of heated air = 1.212 x 10^6/ 1.10x 10^6 = 1.101 g/l The answer is 1.101 g/l.</span>
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Answer:

E_{total}=4.82*10^6N/C

vector with direction equal to the axis X.

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Answer:

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