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ehidna [41]
3 years ago
15

Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk and then immediately jumps up again to celebra

te his basket. When his feet first touch the floor after the dunk, his velocity is 5 m/s downward; when his feet leave the floor 0.50 s later, as he jumps back up, his velocity is 4 m/s upward. a. What is the impulse exerted on Peter during this 0.50 s
Physics
1 answer:
Mars2501 [29]3 years ago
4 0

Answer:

Explanation:

Impulse = change in momentum

Initial momentum = mass x initial velocity = 100 x 5 = 500 kg m/s

final momentum = mass x final velocity = 100 x - 4 = -400 ( - ve sign due to reversal of direction )

change in momentum = final momentum - initial momentum

= - 400 - 500 = - 900 kg m/s .

As it is - ve , it acts upwards .

So magnitude of  impulse on Perter = 900 kg m/s

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When switched on, the grinding machine accelerates from rest to its operating speed of 3550 rev/min in 10 seconds. When switched
Paraphin [41]

Answer:

During start total turns

N_1 = 296 turn

After half of the time total turns

N_3 = \frac{29.6 + 0}{2}(5) = 74 turns

Total number of turns during it stop

N_2 = \frac{59.17 + 0}{2}(31) = 917 turn

After half of the time total turns

N_4 = 688 turns

Explanation:

Initially the machine is at rest and then starts rotating with speed 3550 rev/min

now we will have

f = \frac{3550}{60} = 59.17 rev/s

now we know that it took 10 s to reach the speed

so angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{t}

\alpha = \frac{59.17- 0}{10} = 5.917 rev/s^2

now it stops in 31 s so the angular deceleration is given as

\alpha_2 = -\frac{59.17}{31} = -1.91 rev/s^2

now initially number of turn to reach the given speed

N_1 = \frac{59.17 + 0}{2}(10) = 296 turn

number of turns during it stop

N_2 = \frac{59.17 + 0}{2}(31) = 917 turn

Now during startup speed after t = 5 s is given as

\omega_1 = (5.917)(5) = 29.6 rev/s

N_3 = \frac{29.6 + 0}{2}(5) = 74 turns

now during it stop the speed after half the time is given as

\omega_2 = 59.17 - (1.91)(15.5) = 29.56 rev/s

now the number of turns is given as

N_4 = \frac{59.17 + 29.56}{2}(15.5)

N_4 = 688 turns

5 0
3 years ago
Hermal energy is a form of... A. Potential energy. B. Kinetic energy. C. Chemical energy.
aev [14]

Thermal energy also known as 'heat energy' is a form of kinetic energy.

6 0
3 years ago
At sunrise two old women started to walk towards each other. one started from point a and went towards point b while the other s
konstantin123 [22]

Let the distance between points a and b = d

For the women starting from a her velocity be V_1 and for the women starting from b her velocity be V_2

Let the rising time of sun = x AM

We have  V_1 = \frac{d}{12+4-x}

and we also have  V_2 = \frac{d}{12+9-x}

At they meet means, they both travel a combined distance of d

So we have   V_1*(12-x)+V_2*(12-x)=d

Substituting velocity values we will get

  \frac{d}{12+4-x}*(12-x)+\frac{d}{12+9-x}*(12-x)=d\\ \\ \frac{12-x}{12+4-x}+\frac{12-x}{12+9-x}=1\\ \\ \frac{12-x}{16-x}+\frac{12-x}{21-x}=1\\ \\ 252-21x-12x+x^2+192-12x-16x+x^2=336-16x-21x+x^2\\ \\ x^2-24x+108=0\\ \\ (x-6)(x-18)=0\\ \\

 x= 6 AM or 18 AM, but 18 AM is not possible,

Sun rise time is 6 AM


3 0
3 years ago
A wave has frequency of 50 Hz and a wavelength of 10 m. What is the speed of the wave? Group of answer choices
Fantom [35]

Explanation:

hehshehebdbajahwwdszsjshshs shsbw

6 0
3 years ago
Air resistance is a nonconservative force. It always opposes the motion of an object. An airplane flies from New York to Atlanta
LenKa [72]

Answer:

c) is negative

Explanation:

As we know that work done by a force is the product of force and displacement vector.

W= F.d

F= Force

d= displacement

The work done by friction force always negative because it try to oppose the motion and act opposite to the direction of displacement.So the work done by air resistance is negative.

c) is negative

8 0
3 years ago
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