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kondaur [170]
3 years ago
5

If the planes of a crystal are 3.50 (1 A= 10^-10m = Ångstrom unit) apart, what wavelength of electromagnetic waves are needed so

that the first strong interference maximum in the Bragg reflection occurs when the waves strike the planes at an angle of 22.0 degrees?
Physics
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

λ = 2.62 x 10⁻¹⁰ m = 0.262 nm

Explanation:

We can use Bragg's Law's equation to solve this problem. The Bragg's Law's equation is written as follows:

mλ = 2d Sin θ

where,

m = order of reflection = 1

λ = wavelength = ?

d = distance between the planes of crystal = 3.5 x 10⁻¹⁰ m

θ = strike angle of waves on plane = 22°

Therefore, substituting the respective values in the equation, we get:

(1)λ = (2)(3.5 x 10⁻¹⁰ m)(Sin 22°)

<u>λ = 2.62 x 10⁻¹⁰ m = 0.262 nm</u>

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