How do i solve this?

Mathematics

2 answers:

Ahat [919]3 years ago

8 0

In terms of p, the answer is p= -q-3

Tanya [424]3 years ago

4 0

Step 1: Multiply each side by 9 . (Or by 'q' if that's a 'q'.)

Step 2: Subtract 3 from each side.

You might be interested in

I need help with this question!!

Mashcka [7]

Answer:

QR = 5.

Step-by-step explanation:

Because the parallelograms are similar then the corresponding sides are in the same ratio.

So AB / PQ = BC / QR

9/3 = 15 / QR

15 / QR = 3

QR = 15/3

= 5. (answer)

7 0

3 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

Tim’s bank requires its customers to have a 4-digit personal identification number (PIN) to access their accounts. If each digit

Rina8888 [55]

6,561 is your answer to this question

8 0

3 years ago

Read 2 more answers

If you draw two cards from the deck at the same time, what is the probability that they will both be hearts?

koban [17]

Answer:

The probability is 1/17.