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3 years ago

How do i solve this?

Mathematics

2 answers:

Ahat [919]3 years ago

8 0

In terms of p, the answer is p= -q-3

Tanya [424]3 years ago

4 0

Step 1: Multiply each side by 9 . (Or by 'q' if that's a 'q'.)

Step 2: Subtract 3 from each side.

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What is the factorization of the trinomial below?

valkas [14]

B is the correct answer. hope this helped:)

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2 years ago

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A scaled drawing of a rectangle park is 5 inches wide and 7 inches long. The actual park is 280 yards long. What is the area of

bazaltina [42]

7 inches → 280 yards
1 inch → 280 ÷ 7 = 40 yards
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Area = 280 x 200 = 56 000 yards

Answer: 56000 yards

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3 years ago

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The sixth-graders at Lester's school got to visit either the science museum or the history museum. 21 students picked the scienc

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8 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants

lozanna [386]

Answer:

$y(x)=c_1e^{2ix}+c_2e^{-2ix}$

Step-by-step explanation:

You have the following differential equation:

$3y''+12y=0$ (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

$3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i$

The solution of the differential equation is:

$y(x)=c_1e^{m_1x}+c_2e^{m_2x}$ (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

$y(x)=c_1e^{2ix}+c_2e^{-2ix}$

4 0

3 years ago