Answer:
senior citizen cost $4
children cost $7
Step-by-step explanation:
The question is not complete
<em>Brenda's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 senior citizen tickets and 9 child ... The school took in $67.00 on the second day by selling 8 senior citizen tickets and 5 child tickets. What is the price each of one senior citizen ticket and one child ticket?</em>
Given data
let senior citizens be x
and children be y
so
3x+9y= 75--------------1
on the second day
8x+5y= 67------------2
solve 1 and 2 above
3x+9y= 75 X8
8x+5y= 67 X3
24x+72y=600
-24x+15y=201
0x+57y= 399
divide both sides by 57
y= 399/57
y= $7
put y= 7 in eqn 1 above
3x+9*7= 75
3x+63= 75
3x=75-63
3x=12
x= 12/3
x= $4
Answer: A. 31.5
Step-by-step explanation:
Using law of cosine because it is side angle side
a=16
b=21
angle = 116
c^2=a^2+b^2-2ab cosC, let C be the angle given
c^2=(21)^2+(16)^2-2(16)(21) cos(116)
c^2=441+256-672 cos(116)
i used a ti-89 and answered the right side and got
(you can find a ti-89 simulator online, but for problems like this make sure it is in degree mode)
991.585
c^2=991.585
take square root of both sides
=31.4894, which if you round it up it would be 31.5, so the answer would be A
therefore:
a=16
b=21
c=31.5
-54w-27u+36 because -9 times 6 = 54 and -9 times 3 = 27 and -9 times -4 = 36 so -54w -27 u + 36
Answer:
+
Step-by-step explanation:
