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boyakko [2]
2 years ago
6

1.2 dkg to grams now I have to say extra stuff for it to submit

Chemistry
1 answer:
gtnhenbr [62]2 years ago
3 0

Answer:

12 grams and I have to write something longer so just ignore this

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Griffin made the following list of the different outer coverings of a plant. which part of his list is incorrect?
liraira [26]

Stamen is not an outer covering its the reproductive organ of the plants.

<h3>What is use of covering of Plants ?</h3>

Outer covering of plants is useful in protecting them from environment factors , it is useful in keeping the moisture intact inside the plants.

Among the different outer covering , Bark ,stamen , spines and fuzzy hairs

Bark , stamen and fuzzy hairs are all the outer covering of plants

Stamen is not an outer covering its the reproductive organ of the plants.

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5 0
1 year ago
The wave like behavior of moving particles cannot be observed due to the.........of the particles wavelengths?
Nat2105 [25]
Answer is: 4)Mass

I really hope this helped you out!!!!
7 0
3 years ago
Read 2 more answers
The moving of molecules from areas of high concentration to that of low concentration to gain energy is best described as
seropon [69]

The moving of molecules from areas of high concentration to that of low concentration to gain energy is best described as passive transport

<h3>What is passive transport?</h3>

Passive transport is a type of membrane transport in which chemicals are moved across cell membranes without using energy. Unlike active transport, which uses cellular energy, passive transport uses the second law of thermodynamics to cause the movement of substances across cell membranes.

<h3>Why is passive transport important?</h3>

Passive transport processes are critical to homeostasis. They maintain proper conditions inside the cell and the organism as a whole by letting chemicals to pass into and out of the cell.

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7 0
2 years ago
NItrogen in air reacts at high temperature to form NO2 according to the reaction:
Rina8888 [55]

Answer:

The correct answer is option E.

Explanation:

Structures for the reactants and products are given in an aimage ;

Number of double bonds in oxygen gas molecule = 1

Number of double bonds in nitro dioxide gas molecule = 1

Number of single bond in in nitro dioxide gas molecule = 1

Number of triple bonds in nitrogen gas molecule = 1

N_2+2O_2\rightarrow 2NO_2,\Delta H=?

\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]

\Delta H_{f,NO_2}=33.18 kJ/mol

\Delta H_{f,N_2}=0 (pure element)

\Delta H_{f,O_2}=0 (pure element )

\Delta H=2 mol\times 33.18 kJ/mol=66.36kJ=15.86 kcal

The enthalpy of the given reaction is 15.86 kcal.

6 0
3 years ago
A balloon is inflated such that a radius is 7 cm what is the volume of air inside the balloon in milliliters
DedPeter [7]

Answer:

V=14373.33\ \text{mm}^3

Explanation:

It is given that,

The radius of the inflated balloon is 7 cm.

We need to find the volume of air inside the balloon in milliliters.

The balloon is in the shape of a sphere whose volume is given by :

V=\dfrac{4}{3}\pi r^3\\\\\text{Put r = 7 cm}\\\\V=\dfrac{4}{3}\times \dfrac{22}{7}\times 7\times 7\times 7\\\\V=1437.33\ \text{cm}^3\\\\\text{We know that, 1 cm = 10 mm}\\\\\text{So},\\\\V=14373.33\ \text{mm}^3

Hence, the volume of the air inside the balloon is 14373.33\ \text{mm}^3.

3 0
3 years ago
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