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____ [38]
3 years ago
10

What electrostatic attraction between____ forms an ionic bond?

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0
Between atoms (one metall and one non metall) form an ionic bond(NaCl)
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The concentration of reactant doesn't affect the activity
pashok25 [27]

Answer:

B.false because if the reactant concentration is disturbed the whole reaction will be affected.

Explanation:

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2 years ago
40. Write a balanced equation and a net ionic equation for combining AgNO3(aq) and Na2CO3(aq)
Kay [80]

we are given the the two reactants: AgNO3 and Na2CO3 and is asked to write a balanced equation and a net ionic equation for the reaction of the two. This is a double-replacement reaction:
2AgNO3 (aq)+ Na2CO3 (aq)= Ag2CO3 + 2NaNo3 (aq)
2 Ag + + 2 N03- + 2Na+ + CO32- = Ag2CO3 + 2 Na+ 2NO3-
cancelling the spectator ions, 2Ag + + CO32- = Ag2CO3 
3 0
3 years ago
A client is undergoing therapy in a whirlpool unit that has been plugged into an extension cord. What is this an example of?
frez [133]

Using extension or flexible cords improperly

Explanation:

A client undergoing therapy in a whirlpool unit plugged into an extension cord demonstrates a wrong and improper use of extensions and flexible cords. This is not a safe way to connect an electrical circuit.

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  • The Ground Fault Circuit Interrupter is able to detect leakages in the circuit and breaks it off.

learn more:

electric current brainly.com/question/4438943

#learnwithBrainly

4 0
3 years ago
Which is NOT an example of a solution?
USPshnik [31]
C table snap Lt it is a compound
6 0
3 years ago
Read 2 more answers
A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0
OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL

Putting values in above equation, we get:

2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0
3 years ago
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